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crimeas [40]
2 years ago
10

What do Newton's three laws state?

Physics
1 answer:
guapka [62]2 years ago
8 0
In the first law, we understand that an object will not change its motion unless a force acts on it. The second law states that the force on an object is equal to its mass times its acceleration. And, finally, the third law states that there is an equal and opposite reaction for every action.
You might be interested in
How is sound intensity measured?
muminat

Answer:

Sound intensity is measured with a sound level meter or Sound pressure Level (SPL) Meter.

Explanation:-

It measure sound intensity is the sound pressure level. The unit of measurement is decibels.

7 0
2 years ago
A tuna fish body is streamlined to reduce friction. Which describes the type of friction the fish must overcome?
STatiana [176]
The answer would be Fluid Friction
7 0
3 years ago
Read 2 more answers
How to find acceleration in non uniform motion. Please give two ways
Olenka [21]

<u>The two ways to  find acceleration in non uniform motion are as follows:</u>

  • By Graphs
  • By Calculus

<u>Explanation:</u>

Non-uniform acceleration comprises the most common description of motion. Acceleration refers to the rate of changes of velocity per unit time. Basically, it implies that acceleration changes during motion. This variety can be communicated either as far as position (x) or time (t).

Accordingly, non-uniform acceleration motion can be carried out in 2 ways:

  • By Calculus
  • By graphs

Calculus analysis is general and accurate, but limited to the availability of speed and acceleration expressions. It is not always possible to get the expression of motion attributes in the form "x" or "t". On the other hand, the graphic method is not accurate enough, but it can be used accurately if the graphic has the correct shapes.

The use of calculations involves differentiation and integration. Integration enables evaluation of the expression of acceleration of speed and expression of movement at a distance. Similarly, differentiation allows us to evaluate expression of speed position and expression speed to acceleration.

6 0
3 years ago
Car A starts out traveling at 35.0 km/h and accelerates at 25.0 km/h2 for 15.0 min. Car B starts out traveling at 45.0 km/h and
lawyer [7]

1 kilometre=1000 metre

      1 hour = 3600 second

       1\ km/hr=\frac{1000}{3600} m/s

       1\ km/hr=\frac{5}{18} m/s

The initial velocity of car A is 35.0 km/hr i.e

                                         35.0\ km/hr=35*\frac{5}{18} m/s

                                                                   = 9.72 m/s

The initial velocity of car B is 45 km/hr =12.5 m/s

The initial velocity of car C is 32 km/hr = 8.89 m/s

The initial velocity of car D is 110 km/hr=30.56 m/s

The acceleration of car A is given as  25\ km/hr^2

                                            =\ 25*\frac{1000}{3600*3600} m/s^2

                                            =0.00192901234 m/s^2

The time taken by car A = 15 min.

From equation of kinematics we know that-

                                 v= u+at      [Here v is the final velocity and a is the acceleration and t is the time]

Final velocity of A,  v = 9.72 m/s +[0.00192901234×15×60]m/s

                                   =11.456111106 m/s

The acceleration of B is given as    15\ km/hr^2

                                    =0.00115740740740 m/s^2

The time taken by car B =20 min

The final velocity of B is -

                             v= u+at

                               = u-at    [Here a is negative due to deceleration]

                               =12.5 m/s +[0.0011574074074×20×60]

                               =13.8888888.....

                               =13.9

The acceleration of C is given as    40\ km/hr^2          

                                                            =\ 0.003086419753 m/s^2

The time taken by car C =30 min

The final velocity of C is-

                                v = u+at

                                   =8.89 m/s+[0.003086419753×30×60] m/s

                                   =14.4455555555..m/s

                                   =14.45 m/s

The car C is decelerating.The deceleration is given as-  60\ km/hr^2

                                                                      =0.0046296296296m/s^2

The time taken by car D= 45 min.

The final velocity of the car D is-

                     v =u+at

                        =30.56 -[0.00462962962962×45×60]m/s

                        =18.06 m/s

Hence from above we see that the magnitude of final velocity car C and B is close to 15 m/s. The car C is very close as compared to car B.

                 


3 0
3 years ago
A light bulb operating at a voltage of 120 v has a resistance of 200 ω. what is the power?
cluponka [151]

The correct is 72 watt

We know that formula of power is P=\frac{v^{2} }{r}

so putting the value of Voltage and Resistance in Formula of power so we get

P=\frac{120^{2} }{200} =72

What is Power?

Electric power is the rate at which an electric circuit transfers electrical energy per unit time.

Typically, electricity is generated by generators, but it can also be supplied by sources such as electric batteries. The electric power industry typically distributes it via an electric power grid to businesses and homes (as domestic mains electricity).

Transmission lines allow electric power to be delivered over long distances and used for high-efficiency applications such as motion, light, or heat.  Electric charges are converted to other forms of energy when they pass through an electric potential difference (voltage).

To learn more about Power from the given link:

brainly.com/question/2333114

#SPJ4

4 0
2 years ago
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