Simple interest, I = 101.40
Time, t = 6 years
interest, i = 1.3%
Interest, I=Pit, rearrange
Principal, P=I/(it)=101.40/(6*0.013)=1300
Use SOHCAHTOA. Since we are looking for the hypotenuse, you must use sine or cosine. Since, we are given the adjacent side, use cosine.
cosx=a/h
cos45=8/h
√2/2=8/h
<em>*Cross multiply*</em>
h√2=16
<em>*Divide both sides by √2*</em>
h=16/√2
<em>*Multiply by √2/√2*</em>
h=(16√2)/2
<em>*Simplify the fraction*</em>
h=8√2
Hope this helps!!
Answer: b
Step-by-step explanation:
if u stop imports then u have money
We can withdraw a equation to give mexico population
P = M.(1 + i)^t
So,
First of all, how many years passed? 2015 - 2000 = 15. Our time is 15, our annual rate is 1,7%, time to calc.
P = 100350000.(1 + 1,7%)^15
1,7% = 0,017
P = 100350000.(1 + 0,017)^15
P = 100350000.(1,017)^15
P = 100350000.1,2876988084901218382866596204289
P = 129220575,43198372647206629291004
Rounding
P = 129,220,575
Answer:
5 months
Step-by-step explanation:
We assume that y represents production capacity, rather than <em>increase</em> in production capacity. Then we want to solve the 6th-degree equation ...
x^6 -25x^4 +199x^2 -4975 = 0
This can be factored in groups as ...
x^4(x^2 -25) + 199(x^2 -25) = 0
(x^4 +199)(x^2 -25) = 0
This has 4 complex solutions and 2 real solutions.
x^2 = 25
x = ±5
The duration required for capacity to reach 4975 units is 5 months.
