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Akimi4 [234]
2 years ago
9

1. Multiply and simplify.

Mathematics
1 answer:
Oliga [24]2 years ago
4 0
You have to square it all up then add it up if you want you can use the calculator
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Lilly and Maggie decorated their windows with twinkle lights. Maggie used 51 more twinkle lights than Lilly. Fill in the box wit
nadya68 [22]
We know that
m-------------------- > <span>the amount of twinkle lights Maggie used
l--------------------- >  </span><span>the amount of twinkle lights Lilly used
l=70
m=51+l
therefore
m=51+70=121
m=121

the answer is 121 (</span>amount of twinkle lights Maggie used)
6 0
3 years ago
The circle below has center C, and its radius is 5 in. Given that m
yan [13]
What is the question bruh not everybody know what you talkin bout
7 0
3 years ago
Solve: m + 2/3 = 1/2<br> A. 1 1/6<br> B. 1/6<br> C. -1<br> D-1/6
xxMikexx [17]

I think the answer is (D).

4 0
3 years ago
Read 2 more answers
a Textbook weighs 2.5 pounds. how many kilograms does the textbook weigh? round your answer to the nearest tenth of a pound. one
Rzqust [24]
If you round it to the nearest pound it is 1.1 kg
2.5/2.2 = 1.13....
3 0
3 years ago
Read 2 more answers
A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
3 years ago
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