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aleksklad [387]
4 years ago
9

A 5.5 g sample of a substance contains only carbon and oxygen. Carbon makes up 35% of the mass of the substance. The rest is mad

e of oxygen. You are asked to determine the mass of oxygen in the sample. Which of the following expressions demonstrates a mathematical procedure to solve this problem using the proper order of operations?
Chemistry
1 answer:
bogdanovich [222]4 years ago
8 0
5.5g times ( 1-.35 ) 
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What is an ionic solution and how does it work in a battery?
frutty [35]

Explanation:

An ionic solution is a solution that has anions and cations. This is formed when ionic compounds dissociate in water. The ionic solution can be used as a battery because their respective ions can be attracted to either node of a battery. The cathode (+) attracts anions (negatively charged ions) and the anode (-) attracted cations (positively-charged ions). The reaction between the nodes and the respective ions in the solution causes electrons do be either donated or received. This ensures that the ionic solution (electrolyte) acts as channels for transport of electrons across the nodes to complete a circuit.

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8 0
3 years ago
Which sample of matter has a crystal structure?
Maurinko [17]
The correct answer:C) NaCl(s)
Hope this helps!
4 0
4 years ago
What happened to the size of the sun one carbon and oxygen
Ainat [17]

Answer:

Explanation:

The volume of the Sun is so huge that it could hold over 1 million Earths. The Sun is a typical star, and is also the star that is nearest to the Earth. It is composed of a mixture of 73% hydrogen, 25% helium, and 2% other elements by weight.

4 0
3 years ago
A sample of sodium sulfite has a mass of 2.80 g.
Gnom [1K]

<u>Answer:</u>

<u>For a:</u> The number of sodium ions in given amount of sodium sulfite are 2.65\times 10^{22}

<u>For b:</u> The number of sulfite ions in given amount of sodium sulfite are 1.325\times 10^{22}

<u>For c:</u> The mass of one formula unit of sodium ions is 2.09\times 10^{-22} grams

<u>Explanation:</u>

The chemical formula of sodium sulfite is  Na_2SO_3. It is formed by the combination of 2 sodium (Na^+) ions and 1 sulfite (SO_3^{2-}) ions

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of sodium sulfite = 2.80 g

Molar mass of sodium sulfite = 126 g/mol

Putting values in above equation, we get:

\text{Moles of sodium sulfite}=\frac{2.80g}{126g/mol}=0.022mol

  • <u>For a:</u>

Moles of sodium ions in sodium sulfite = (2 × 0.022) moles

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of particles

So, 0.022 moles of sodium sulfite will contain = (2\times 0.022\times 6.022\times 10^{23})=2.65\times 10^{22} number of sodium ions

Hence, the number of sodium ions in given amount of sodium sulfite are 2.65\times 10^{22}

  • <u>For b:</u>

Moles of sulfite ions in sodium sulfite = (1 × 0.022) moles

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of particles

So, 0.022 moles of sodium sulfite will contain = (1\times 0.022\times 6.022\times 10^{23})=1.325\times 10^{22} number of sulfite ions

Hence, the number of sulfite ions in given amount of sodium sulfite are 1.325\times 10^{22}

  • <u>For c:</u>

Molar mass of sodium sulfite = 126 g/mol

According to mole concept:

6.022\times 10^{23} number of formula units are present in 1 mole of a compound

Or, 6.022\times 10^{23} number of formula units of sodium sulfite have a mass of 126 grams

So, 1 formula unit of sodium sulfite will have a mass of = \frac{126}{6.022\times 10^{23}}\times 1=2.09\times 10^{-22}g

Hence, the mass of one formula unit of sodium ions is 2.09\times 10^{-22} grams

7 0
3 years ago
Calculate the change in energy when 75.0 grams of water drops from<br> 31.0C to 21.6.
zysi [14]

Answer: Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

oC

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

o

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

5 0
3 years ago
Read 2 more answers
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