Answer:
a) Ag(NH₃)₂⁺, Cl⁻.
b) NH₃.
c) AgCl.
Explanation:
Based on LeChatelier's law, a system in chemistry can change responding to a disturbance of concentration, temperature, etc. in order to restore a new state.
In the reaction:
AgCl(s) + 2NH₃(aq) ⇌ Ag(NH₃)₂⁺(aq) + Cl⁻(aq)
When reactants are added, the system will produce more products restoring the equilibrium and vice versa. A reactant in solid state doesn't take part in the equilibrium, thus:
a) Ag(NH₃)₂⁺, Cl⁻. The addition of products will shift the equilibrium to the left
b) NH₃. The addition of reactant will shift the equilibrium to the right.
c) As AgCl is in solid phase, will not shift the equilibrium in either direction.
Answer:
Volume of N₂ = 14.76 L
Volume of H₂ = 29.52 L
Explanation:
Given data:
Mass of N₂H₄ formed = 28.5 g
Pressure = 1.50 atm
Temperature = 30°C (30+273 = 303 k)
Volume of N₂ and H₂ needed = ?
Solution:
Chemical equation:
N₂ + 2H₂ → N₂H₄
Number of moles of N₂H₄ formed = mass/ molar mass
Number of moles of N₂H₄ formed = 28.5 g/ 32 g/mol
Number of moles of N₂H₄ formed = 0.89 mol
Now we will compare the moles of N₂H₄ with N₂ and H₂ form balance chemical equation.
N₂H₄ : N₂
1 : 1
0.89 : 0.89
N₂H₄ : H₂
1 : 2
0.89 : 2×0.89 = 1.78 mol
Volume of H₂:
PV = nRT
1.50 atm × V = 1.78 mol × 0.0821 atm.L/mol.K × 303 K
V = 44.28atm.L /1.50 atm
V = 29.52 L
Volume of N₂:
PV = nRT
1.50 atm × V = 0.89 mol × 0.0821 atm.L/mol.K × 303 K
V = 22.14 atm.L /1.50 atm
V = 14.76 L
F---atomic number 9---1s2 2s2 2p5 -----7 electrons
answer is atom.Hope it is helpful.
Answer:
6.56×10¹⁴ Hz
Explanation:
From the question given above, the following data were obtained:
Wavelength = 457 nm
Frequency =?
Next, we shall convert 457 nm to metre (m). This can be obtained as follow:
1 nm = 1×10¯⁹ m
Therefore,
457 nm = 457 nm × 1×10¯⁹ m / 1 nm
457 nm = 4.57×10¯⁷ m
Thus, 457 nm is equivalent to 4.57×10¯⁷ m
Finally, we shall determine the frequency of the blue light as follow:
Wavelength = 4.57×10¯⁷ m
Velocity of light = 3×10⁸ m/s
Frequency =?
Velocity = wavelength x frequency
3×10⁸ = 4.57×10¯⁷ × frequency
Divide both side by 4.57×10¯⁷
frequency = 3×10⁸ / 4.57×10¯⁷
frequency = 6.56×10¹⁴ Hz
Therefore, the frequency of the blue light is 6.56×10¹⁴ Hz
