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Setler79 [48]
3 years ago
7

Kati was in the kitchen when she heard a crash. She went into her bedroom and found her window broken and a baseball lying on th

e ground. Kati said "this baseball broke my window." This statement is an
Chemistry
2 answers:
Alexus [3.1K]3 years ago
6 0
The answer is inference
mart [117]3 years ago
5 0

Answer:  inference because she drew a conclusion based on evidence.

why?:

Because the evidence was that she heard the crashing sound, and then when she came into her room saw the broken window and baseball.

It was not an observation because she did not directly see the baseball going through the window

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A sample has a pH of -0.248 (yes, it really is possible to have a negative pH). Find
dalvyx [7]

Answer:

pOH= 14.248

[H+]=1.77 M

[OH-]=5.65 x10^-15M

Explanation:

pH+pOH= 14

pOH= 14-pH

pOH=14-(-0.248)

pOH= 14.248

[H+]=10^-pH= 10^-(-0.248)=1.77 M

[OH-]=10^-pOH= 10^-14.248=5.65 x10^-15M

5 0
3 years ago
Manganese-56 is a beta emitter with a half-life of 2.6 hours. What is the mass of
Arisa [49]

Answer:

0.0009765625

Explanation: u just keep doing a half life till it goes to 13 aka

8.0g divided by 2  till you reach to 13 times of a half life ;p

8 0
3 years ago
Read 2 more answers
How are the formulas and names of ionic compounds written
MA_775_DIABLO [31]
Put the cation (a positive ion, the metal in this case,) without changing anything, then the nonmetal, or anion. For the nonmetal, change the ending to -ide. For example, if you have potassium and chlorine, you would have potassium chloride. Hope this helps!
3 0
3 years ago
Which statements regarding the Henderson-Hasselbalch equation are true? If the pH of the solution is known as is the pKa for the
Sonbull [250]

Answer:

1, 2, and 3 are true.

Explanation:

The Henderson-Hasselbalch equation is:

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

  • If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If you know pH and pka:

10^(pH-pka) = \frac{[A^-]}{[HA]}

The ratio will be: 10^(pH-pka)

  • At pH = pKa for an acid, [conjugate base] = [acid] in solution. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

0 = log₁₀ \frac{[A^-]}{[HA]}

10^0 = \frac{[A^-]}{[HA]}

1 = \frac{[A^-]}{[HA]}

As ratio is 1,  [conjugate base] = [acid] in solution.

  • At pH >> pKa for an acid, the acid will be mostly ionized. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If pH >> pKa,  10^(pH-pka) will be >> 1, that means that you have more [A⁻] than [HA]

  • At pH << pKa for an acid, the acid will be mostly ionized. <em>FALSE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If pH << pKa,  10^(pH-pka) will be << 1, that means that you have more [HA] than [A⁻]

I hope it helps!

6 0
3 years ago
4. Which of the following is NOT a common property of bases? A. Feels slippery B. tastes bitter C. Reacts with metal D. Changes
alisha [4.7K]

Reacting with metals is not a common property of bases. Bases do however react with acids. 

3 0
4 years ago
Read 2 more answers
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