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VLD [36.1K]
3 years ago
12

PLEASE ANSWER ASAP!!

Mathematics
1 answer:
denis23 [38]3 years ago
3 0
A & D are the correct answers!! I hope this helps
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What is the length of the radius of a circle with a center at 2 – i and a point on the circle at 8 + 7i?
AlladinOne [14]
We need to find a distance between this to points.
D=√((x2-x1)²+(y2-y1)²)

For complex plain, the real part of the complex number plays a role of x,
and  number of an imaginary part plays a role of y.
So,
D=√((8-2)² +(7+1)²)√ = √(36+64)=√(100)=10
Answer is D.10
8 0
3 years ago
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Anybody who want extra points I can give it too you, NOT A JOKE I AM SERIOUS.
alexira [117]

Answer:

? 40.50

Step-by-step explanation:

90 ÷ 20 × 9 = 40.5

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3 years ago
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The university is on a bearing of 050 degrees from the stadium and 300 degrees from the hospital. Mark the position of the unive
Licemer1 [7]

Answer:

Check Explanation

Step-by-step explanation:

The map isn't available, but, one can draw this bearings with the descriptions given

Angles for bearings are usually drawn, reading from the north direction.

A sketch of the described bearings and locations of the stadium, university and the hospital is presented in the attached image to this question.

For the sketch on the map.

On The map, draw a four-cardinal points' cross at the stadium draw a line from the bearing 050° from the stadium's four cardinal points' cross. Leave the line as it is.

Then, draw another four cardinal points' cross at the hospital and draw a line from the bearing 300° from the hospital's four cardinal points' cross.

Wherever the line from the hospital meets the line from the stadium, is where the University is located.

Hope this Helps!!!!

6 0
3 years ago
State whether the equation represents exponential​ growth, exponential​ decay, or neither.
raketka [301]

Answer:

Sryy

Step-by-step explanation:

i just need points

3 0
3 years ago
Please help 50 points
tankabanditka [31]

Answer:

See attached

Step-by-step explanation:

Table filled in, see picture

  1. The first column contains points with coordinates (x, y)
  2. The second column contains the rule (x + (-4), y + 2)
  3. The third column is obtained by applying the rule. Showing this for one of the vertices:
  • Q: (1, 4)
  • Apply rule: (1 + (-4), 4 + 2) = (1 - 4, 6) = (-3, 6)
  • Get coordinates of Q' from previous step: (-3, 6)

So you get Q'(-3, 6) from Q(-1, 4) by applying the rule (x + (-4), y + 2).

Same steps for other vertices done and shown in the table.

Hope it is more clear.

6 0
3 years ago
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