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2 years ago

a band earns 2/3 from ticket sales and 1/5 from merchandise. the band earns 1500 in ticket sales. how much from merchandise

2 answers:

6 0

If the band is earning $1,500 on ticket sales, that is equal to 2/3 aka 6/15. (found by multiplying the fraction by 3/3 aka 1) 1/5 aka 3/15 is earned on merchandise. Since 3/15 is half of 6/15, that means that merchandise makes half of $1,500, (1500÷2) or $750.

So, the band earns $750 from merchandise :)

kotegsom [21]2 years ago

4 0

Answer: $750

Step-by-step explanation:

If the band is earning $1,500 on ticket sales, that is equal to 2/3 aka 6/15. 1/5,or, 3/15 is earned on merchandise. Since 3/15 is half of 6/15, that means that merchandise makes half of $1,500, (1500÷2) or $750.

So, the band earns $750 from merchandise

750

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2 years ago

A standard six-sided die is rolled twice and the top faces are observed. What is the probability that the sum of the numbers on

melisa1 [442]

Answer:

A standard six-sided die is rolled twice and the top faces are observed and the probability that the sum of the numbers on the top faces is 10 is $\frac{1}{12}$

Solution:

The sample space of two dice outcomes is given as follows:

{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3, 1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4, 1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5, 1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6, 1) (6,2) (6,3) (6,4) (6,5) (6,6) }

Total number of events n(s) = 36

Expected Outcomes = {(4, 6), (5, 5), (6, 4)}

Number of favorable outcomes n(E) = 3

Probability (sum of numbers on the top faces is 10) = $\frac{n(E)}{n(s)}$ = $\frac{3}{36}$ = $\frac{1}{12}$

Therefore the probability that the sum of the numbers on the top faces is 10 is $\frac{1}{12}$

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