Answer:
a. The sampling distribution will be approximately normal.
d. The mean of the sampling distribution will be close to 52%
g. The standard deviation of the sampling distribution will be 0.0408
Step-by-step explanation:
For this problem the sample size is large enough (n>30), and then the sampling distribution
would be approximately normal. The mean of the sampling distributions is given by ![p=0.52](https://tex.z-dn.net/?f=p%3D0.52)
The expected value for the sampling distribution would be 0.52 since ![E(\hat p) = p](https://tex.z-dn.net/?f=E%28%5Chat%20p%29%20%3D%20p)
And for the standard deviation we know that is given by:
![Sd= \sqrt{\frac{p (1-p)}{n}}=\sqrt{\frac{0.52(1-0.52)}{150}}=0.0408](https://tex.z-dn.net/?f=Sd%3D%20%5Csqrt%7B%5Cfrac%7Bp%20%281-p%29%7D%7Bn%7D%7D%3D%5Csqrt%7B%5Cfrac%7B0.52%281-0.52%29%7D%7B150%7D%7D%3D0.0408)
So the correct answers on this case are:
a. The sampling distribution will be approximately normal.
d. The mean of the sampling distribution will be close to 52%
g. The standard deviation of the sampling distribution will be 0.0408