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2 years ago

Is the square root of 18 closer to 4 or 5

Mathematics

2 answers:

Kazeer [188]2 years ago

8 0

It’s closer to 4 because 18 is closer to 16

natulia [17]2 years ago

4 0

Answer:

it should be closer to 4 because 18 is closer to 16.

Step-by-step explanation:

You might be interested in

No work needed, just need answer please.

In-s [12.5K]

Answer:

1 is 27.8%

2 is 41.7%

Step-by-step explanation:

To calculate 1 there is a 10/36 chance (2, 3, 4, 5 out of possible roles of 2 - 12)

To calculate 2 there is a 15/36 chance (2, 3, 5, 7, 11 are prime)

7 0

2 years ago

Given m||n, find the value of x. kt (7-10) (6x-5)°

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

So, leets look at the graph.

We can see that the lines being solved for tecnically make up 180 degrees.

This is because the value of the angles on line m are equal to the value of the angles on line n.

So, we know that the total line, 180 degrees, is 7x-10, and 6x-5.

Lets combine these two equations, and subtract them from 180 degrees to solve for x:

7x-1+6x-5

13x-15

Now to solve for x:

13x-15=180

Add 15 to both sides to get 13x alone:

13x=195

Then divide both sides by 13 to get x alone:

x=15

So our value of x is 15!

Hope this helps! :)

3 0

2 years ago

What mathematical sentence is represented by the diagram?

cricket20 [7]

My only guess is a^2 + b^2 = c^2

7 0

2 years ago

Question 1 Find the Mean of the following set of data values. 46, 57, 68, 63, 49, 52, 61, 68

Zielflug [23.3K]

The mean would be 58!! Basically what you’re doing to get the mean is adding all of the numbers together and dividing by how many you’re adding. In this case, you would add all of the numbers and divide by 8 because you have 8 numbers ! :D

3 0

1 year ago

The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te

kozerog [31]

Answer:

$\dfrac{6}{7}$ .

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

$a_n=ar^{n-1}$

$a+ar=6$ ...(1)

Each term is 5 times the sum of the succeeding terms.

$a_n=5(a_{n+1}+a_{n+2}+...+\infty)$

$ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)$

$ar^{n-1}=5ar^n(1+r+r^2+...+\infty)$

Divide both sides by a.

$r^{n-1}=5r^n(\dfrac{1}{1-r})$ $[\text{Sum of infinite GP}=\dfrac{a}{1-r}]$

$\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}$

$\dfrac{1}{r}=\dfrac{5}{1-r}$

$1-r=5r$

$1=6r$

$\dfrac{1}{6}=r$

The common ratio is 1/6.

Put r=1/6 in (1).

$a+a(\dfrac{1}{6})=6$

$6a+a=36$

$7a=36$

$a=\dfrac{36}{7}$

Second term $ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}$

Therefore, the second term is $\dfrac{6}{7}$ .

4 0

2 years ago