Which of the following are vertical asymptotes of the function y=3cot(1/2x)-4? A. 3pi B. 2pi C. pi/2 D. 0

Mathematics

2 answers:

Rina8888 [55]3 years ago

5 0

Answer:

B and D

Step-by-step explanation:

puteri [66]3 years ago

4 0

A vertical asymptote occurs when function limit goes to infinity.

cot is reciprocal of tangent.

cot = 1/tan, Find where tan = 0, since 1/0 goes to infinity.

tan(a) = 0 when a = 0,pi

Now Apply coefficient inside cot function.
x/2 = 0,pi
x = 0, 2pi

Therefore, vertical asymptotes occur when x = 0 or 2pi

You might be interested in

Which table of values represents the equation Y= 2X +5?

barxatty [35]

Answer:

Step-by-step explanation:

212113

8 0

2 years ago

PLEASE HELP !!!!!!! Jordan got a new money bank for his birthday with $20 inside. He puts part of his weekly allowance in his ba

kupik [55]

Answer:

Slope of the function is $=3.75$ ,Y-intercept $=20$ .

The function is $y=3.75(x)+20$ with initial value $=20$ ,Jordan puts $\$3.75$ each week andthe amount saved by Jordan after $52$ week $=215\$$ .

Step-by-step explanation:

To understand the slope and y-intercept lets assign $x$ as number of weeks and $y$ as the money saved by Jordan.

Jordan is already having a sum of $\$20$ inside the money bank so in $0$ week the amount is $\$20$ can be written as $(x,y) =(0,20)$ in coordinate form.

SImilarly

We have $(x,y) =(0,20)$ and $(x_1,y_1) =(25,113.75)$

Part A:

The function is $y=m(x)+b$

From point-slope form,we have slope (m)

and $m=\frac{y_1-y}{x_1-x}$ ,plugging the values of the points.

$m=\frac{113.75-20}{25-0}=3.75$

Y-intercept of this function is the constant term or the money of $\$20$ that is already inside the money bank.

We can also calculate y-intercept by arranging the function as $b=y-m(x)$ choosing any $(x_1,y_1) = (25,113.75)$ coordinate and here $b$ is the y-intercept.