Utilizando proporciones, hay que el pick-up más grande carga 5250 kg.
- Este problema se resuelve por proporciones, por médio de una regla de três.
El peso que cargan tres pick-ups están en la razón de 2:6:7
- 2 + 6 + 7 = 15.
- O sea, el pick-up menor carga
de el total, que es equivalente a 1500 kg. - El pick-up más grande carga
de el total, que es equivalente a x kg.
La regla de três es:
- 1500 kg
- x kg
Aplicando multiplicación cruzada:




El pick-up más grande carga 5250 kg.
Un problema similar es dado en brainly.com/question/24615636
All real numbers / all x
if you're asking for range as well then its -1<x<1
Answer:
Step-by-step explanation:
since the data is already arranged in ascending to descending u don't have to change.
upper quartile (Q3) = 3(n + 1)/4 (n means no of data)
=3(10 + 1)/4
=3*11/4
=33/4
=8.25
=8 th term + 0.25(9 th term - 8 th term)
=11 + 0.25(13 - 11)
=11 + 0.25*2
=11 + 0.5
=11.5