Idk tbh I think you can search that up
The given equation for the relationship between a planet's orbital period, T and the planet's mean distance from the sun, A is T^2 = A^3.
Let the orbital period of planet X be T(X) and that of planet Y = T(Y) and let the mean distance of planet X from the sun be A(X) and that of planet Y = A(Y), then
A(Y) = 2A(X)
[T(Y)]^2 = [A(Y)]^3 = [2A(X)]^3
But [T(X)]^2 = [A(X)]^3
Thus [T(Y)]^2 = 2^3[T(X)]^2
[T(Y)]^2 / [T(X)]^2 = 2^3
T(Y) / T(X) = 2^3/2
Therefore, the orbital period increased by a factor of 2^3/2
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Answer:
/2
Step-by-step explanation:
lets find hypotenuse( longest side) first
let other two samller sides be a and b and hypotenuse be c
pythagorsd theorem
a^2 + b^2 =c^2
9^2 + 2^2 =c^2
81 + 4=c^2
85 =c^2
=c
take theta as reference angle
cosec theta=hypotenuse/opposite
=
/ 2
Answer:
(x+9)(3x+27)
Step-by-step explanation:
3x^2+54x+243 (243×3=729, Product=729, Sum=54) [27+27=54, 27×27=729]
3x^2+27x+27x+243
3x(x+9)+27(x+9)
=(x+9)(3x+27)
Perpendicular or Infinitely long prob perpendicular.