1/-x*5y/-8
-1/x × (-5y/8)
5y/8x
In the
plane, we have
everywhere. So in the equation of the sphere, we have

which is a circle centered at (2, -10, 0) of radius 4.
In the
plane, we have
, which gives

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.
In the
plane,
, so

which is a circle centered at (0, -10, 3) of radius
.
The answer is 1. 15a2-19ab-56b2
In the given graph :
y - intercept of the line (c) is :
let's find slope (m) :
now, let's equate it with general equation to find the equation of line,
m = -2
c = 2
therefore, the equation of line will be :
48 I’m pretty sure sorry if it’s wrong