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Nuetrik [128]
3 years ago
9

Find the center and radius, then write the standard equation of this circle

Mathematics
1 answer:
kirza4 [7]3 years ago
8 0

Center is at (0, 0) and make sure you label it on the diagram
Radius is 5 units
Equation of circle is
(X-0)^2 + (y-0)^2 = 5^2
X^2 + y^2 = 25
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Dagogo uploads 3 videos on his channel every month. Each video averages 15 minutes in length and gets an average of 150,000 new
Lana71 [14]

Answer: 20 months

Step-by-step explanation:

x months times y for views over 1 month = 9000000 views

3 x 150000(views per video) = 450000

9000000/450000= 20 months

4 0
2 years ago
Mr. Roseanne will buy 12 1/2 pounds beef for for a cookout. The price for the first 3 pounds of beef is $4.99 per pound. After t
Yuri [45]

Answer:

As per the statement:

Mr. Roseanne will buy 12\frac{1}{2} pounds beef for for a cookout.

⇒ Weight of the beef he buy = \frac{25}{2} pounds.

It is given that:

The price for the first 3 pounds of beef is $4.99 per pound.

then;

the price for 3 pounds he will pay= 3 \times 4.99 =\$ 14.97

After that, the price is $4.49 per pound.

Remaining weight of beef left  = \frac{25}{2} -3 = \frac{19}{2} pounds.

then;

the price of \frac{19}{2} pounds he will pay = \frac{19}{2} \times 4.49= \$42.655

now, total money he will pay for the 12\frac{1}{2} pounds beef = 14.97+42.655 = \$57.625

Therefore, $57.625 will Mr. Roseanne pay for the beef


4 0
3 years ago
50 points!!
Anika [276]

Step-by-step explanation:

The average speed is distance over time.

34 mi / 0.5 hr = 68 mph

Therefore, the driver must have been speeding at some point between the two toll booths.

4 0
3 years ago
Find the equation of a parabola with a vertical axis and its vertex at the origin and passing through the point (-2, 3)
vredina [299]

a vertical axis, I assume it means a vertical axis of symmetry, thus it'd be a vertical parabola, like the one in the picture below.

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \qquad \leftarrow vertical\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=0\\ k=0 \end{cases}\implies y=a(x-0)^2+0 \\\\\\ \textit{we also know that } \begin{cases} x=-2\\ y=3 \end{cases}\implies 3=a(-2-0)^2+0\implies 3=4a \\\\\\ \cfrac{3}{4}=a~\hspace{10em}y=\cfrac{3}{4}(x-0)^2+0\implies \boxed{y=\cfrac{3}{4}x^2}

8 0
3 years ago
Suppose that 2 ≤ f '(x) ≤ 4 for all values of x. What are the minimum and maximum possible values of
Vesna [10]

Answer:

Step-by-step explanation:

By the Mean Value Theorem, there is at least one number, c, in the interval (1,6) such that

f'(c) = [f(6) - f(1)]/ (6 - 1)

So, f(6) - f(1) = 5f'(c).

Since 2 ≤ f'(c) ≤ 4, 10 ≤ 5f'(c) ≤ 20

So, f(6) - f(1) is between 10 and 20.  

5 0
2 years ago
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