Answer: W = 0.3853 J, e = 0.052 m
Explanation: Given that,
K =285.0N/M , L = 0.230m , F = 15N , e = ?
F = Ke
15 = 285 × e
e = 15÷ 285
e =0.052 m
e + L = 0.052 + 0.230
= 0.282m ( spring new length )
Work needed to stretch the spring
W = 1/2ke2
W = 1/2 × 285 x 0.052 × 0.052
W = 0.3853 J
Answer:
T=Lnsin
Please check the attached
Explanation:
The torque can simply be calculated by multiplying the length of the rod by the perpendicular force n as shown in the attached figure.
Note that sin90=1
T=Lsin
(nsin90)
T=Lsin
xn
T=Lnsin
Answer:
1. 24375 N/C
2. 2925 V
Explanation:
d = 12 cm = 0.12 m
F = 3.9 x 10^-15 N
q = 1.6 x 10^-19 C
1. The relation between the electric field and the charge is given by
F = q E
So, 

E = 24375 N/C
2. The potential difference and the electric field is related by the given relation.
V = E x d
where, V be the potential difference, E be the electric field strength and d be the distance between the electrodes.
By substituting the values, we get
V = 24375 x 0.12 = 2925 Volt