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balu736 [363]
4 years ago
15

Please help again with the following 2 questions

Mathematics
1 answer:
yuradex [85]4 years ago
3 0
Perimeter top one:
5+1+2+3+3+4= 18in

Perimeter bottom one:
6+1+4+3+2+4= 20in


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Q: THE PERPENDICULAR SIDES OF A RIGHT ANGLED TRAINGLE ARE 12 AND 15 CENTIMETERS LONG. ANOTHER RIGHT ANGLED TRAINGLE OF THE SAME
garri49 [273]

Area of a right triangle is 1/2 x height x base

The area of the first triangle is 1/2 x 12 x 15 = 90 square cm.

The area of the other triangle is 90 and one side is 18:

90 = 1/2 x 18 x S

Multiply both sides by 2:

180  = 18 x S

Divide both sides by 18:

S = 180/18

S = 10

The length of the other side is 10 centimeters

5 0
3 years ago
Read 2 more answers
All of the following are equivalent except: 5 is to 3; 45/27; 15/5; 7.5:4.5
uysha [10]
I'm thinking either 5 is to 3 or 45/27
8 0
4 years ago
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A rock is thrown from the top of a building. The graph shows the height, y, of the rock from the ground after x seconds. At what
Marta_Voda [28]

Answer:

C.

Step-by-step explanation:

7 0
3 years ago
Can I get an example of systems of equations that represent the solution of this situation below? Thank you! ^ ^
Alenkinab [10]

Answer:

1x+ 1y =11

10x + 5y = 80

x = the cost of a taco = $5

y = the cost of a burrito = $6

Step-by-step explanation:

x = the cost of a taco

y = the cost of a burrito

1x+ 1y =11

10x + 5y = 80

rearange 1st equation as y = 11 -x and plug in into the 2nd one for y:

10x + 5( 11-x) = 80 distribute left side

10x + 55 - 5x = 80 combine like terms

10x - 5x = 5x

5x + 55 = 80 subtract 55 from both sides

5x = 80 - 55

5x = 25 divide by 5

x = 5

plug in for y in 1st equation y = 11--x =11-5 = 6

7 0
4 years ago
A <br> B <br> C or D please help
julia-pushkina [17]
The answer is c hope u get it rt
7 0
3 years ago
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