Answer:
0.193 L
Explanation:
Step 1:
Data obtained from the question.
Initial Volume (V1) = 0.250 L
Initial temperature (T1) = 27°C
Initial pressure (P1) = 0.850 atm
Final volume (V2) =?
Final temperature (T2) = 0°C
Final pressure (P2) = 1.00 atm
Step 2:
Conversion of celsius temperature to Kelvin temperature.
Temperature (Kelvin) = temperature (celsius) + 273
Initial temperature (T1) = 27°C = 27°C + 273 = 300K
Final temperature (T2) = 0°C = 0°C + 273 = 273K
Step 3:
Determination of the new volume of the sample of ammonia gas.
The new volume can be obtain by using the general gas equation as shown below:
P1V1/T1 = P2V2/T2
0.850x0.250/300 = 1xV2/273
Cross multiply to express in linear form
300 x V2 = 0.850x0.250x273
Divide both side by 300
V2 = (0.850x0.250x273) /300
V2 = 0.193 L
Therefore, the volume of the sample at 0 °C and 1.00 atm is 0.193 L
