You would have to use the ideal gas law for this:
PV=nRT
Pressure, Volume, n=moles, R gas constant, Temperature in Kelvin
P=nRT/V
(1.8mol)(62.36)(309K)/43.0L = 805mm Hg
Consumer or it might be a want... more than likely a consumer.
Moles of Fe2O3 used : 3.83
<h3>Further explanation</h3>
Given
11.5 moles of CO2
Required
moles of Fe2O3
Solution
Reaction
<em>Fe2O3 + 3CO ⇒2Fe + 3CO2 </em>
The reaction coefficient shows the mole ratio of the reacting compound (reactants or products)
From the equation, mol ratio of Fe2O3 : CO2 = 1 : 3, so mol Fe2O3 :
= 1/3 x moles CO2
= 1/3 x 11.5
= 3.83 moles
Answer:
6gkwkskekekkr
Explanation:
jakksksksjjdjdjdjdjdjdkskjj
Answer:
869.93J/g°C
Explanation:
From the question given, we obtained the following:
M = 42.6g
T1 = 12°C
T2 = 46°C
ΔT = T2 — T1 = 46 — 12 = 34°C
C =?
Q = 1260 KJ = 1260000J
Q = MCΔT
C = Q / MΔT
C = 1260000 /(42.6 x 34)
C = 869.93J/g°C
Therefore, the specific heat capacity is 869.93J/g°C
