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Varvara68 [4.7K]
2 years ago
15

Chemical analysis shows that citric acid contains 37.51% C, 4.20% H, and 58.29% O. What is the empirical formula for citric acid

?​
Chemistry
1 answer:
Fiesta28 [93]2 years ago
7 0

The empirical formula for the citric acid is C₆H₈O₇

<h3>Data obtained from the question </h3>
  • Carbon (C) = 37.51%
  • Hydrogen (H) = 4.20%
  • Oxygen (O) = 58.29%
  • Empirical formula =?

Divide by their molar mass

C = 37.51 / 12 = 3.126

H = 4.2 / 1 = 4.2

O = 58.29 / 16 = 3.643

Divide by the smallest

C = 3.126 / 3.126 = 1

H = 4.2 / 3.126 = 1.34

O = 3.643 / 3.126 = 1.17

Multiply through by 6 to express in whole number

C = 1 × 6 = 6

H = 1.34 × 6 = 8

O = 1.17 × 6 = 7

Thus, the empirical formula for the citric acid is C₆H₈O₇

Learn more about empirical formula:

brainly.com/question/24818135

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Olegator [25]

Answer:

1. 0.178 moles ; 2. 8x10²³ atoms ; 3. 7.22x10²³ molecules ; 4. 89.6 g ; 5. 1.34x10²² atoms ; 6. 1.67x10²⁵ molecules

Explanation:

1. Mass / Molar mass = Mol

5g / 28 g/m = 0.178 moles

2. 1 molecule of N₂ has 2 atoms, it is a dyatomic molecule.

4x10²³  x2 = 8x10²³ atoms

3. 1 mol of anything, has 6.02x10²³ particles

6.02x10²³ molecules . 1.2 mol = 7.22x10²³

4. 1 atom of C weighs 12 amu.

4.5x10²⁴ weigh ( 4.5x10²⁴ . 12) = 5.24x10²⁵ amu

1 amu = 1.66054x10⁻²⁴g

5.24x10²⁵ amu = (5.24x10²⁵ . 1.66054x10⁻²⁴) = 89.6 g

5. Molar mass NaCl = 58.45 g/m

1.3 g /  58.45 g/m = 0.0222 moles

1 mol has 6.02x10²³ atoms

0.0222 moles → ( 0.0222 . 6.02x10²³) = 1.34x10²²

6. Density of water is 1 g/mL, so 500 mL are contained in 500 g of water

Molar mass H₂O = 18 g/m

500 g / 18 g/m = 27.8 moles

6.02x10²³ molecules . 27.8 moles = 1.67x10²⁵

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7,000 μg = 7,000 × 0.000001 g = 0.007 g

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