Ask question

Ask question

All categories

Varvara68 [4.7K]

1 year ago

15

Chemical analysis shows that citric acid contains 37.51% C, 4.20% H, and 58.29% O. What is the empirical formula for citric acid

?

1 answer:

Fiesta28 [93]1 year ago

7 0

The empirical formula for the citric acid is C₆H₈O₇

<h3>Data obtained from the question </h3>

Carbon (C) = 37.51%

Hydrogen (H) = 4.20%

Oxygen (O) = 58.29%

Empirical formula =?

Divide by their molar mass

C = 37.51 / 12 = 3.126

H = 4.2 / 1 = 4.2

O = 58.29 / 16 = 3.643

Divide by the smallest

C = 3.126 / 3.126 = 1

H = 4.2 / 3.126 = 1.34

O = 3.643 / 3.126 = 1.17

Multiply through by 6 to express in whole number

C = 1 × 6 = 6

H = 1.34 × 6 = 8

O = 1.17 × 6 = 7

Thus, the empirical formula for the citric acid is C₆H₈O₇

Learn more about empirical formula:

brainly.com/question/24818135

You might be interested in

Penicillinase, also known as β‑lactamase, is a bacterial enzyme that hydrolyzes and inactivates the antibiotic penicillin. Penic

sergeinik [125]

Explanation:

The given data is as follows.

$V_{max} = 6.8 \times 10^{-10} \mu mol/min$

$K_{m} = 5.2 \times 10^{-6} M$

Now, according to Michaelis-Menten kinetics,

$V_{o} = V_{max} \times [\frac{S}{(S + Km)}]$

where, S = substrate concentration = $10.4 \times 10^{-6}$ M

Now, putting the given values into the above formula as follows.

$V_{o} = V_{max} \times [\frac{S}{(S + Km)}]$

$V_{o} = 6.8 \times 10^{-10} \mu mol/min \times [\frac{10.4 \times 10^{-6} M}{(10.4 \times 10^{-6}M + 5.2 \times 10^{-6} M)}]$

$V_{o} = 6.8 \times 10^{-10} \mu mol/min \times 0.667$

= $4.5 \times 10^{-10} \mu mol/min$

This means that $V_{o}$ would approache $V_{max}$ .

5 0

3 years ago

Assume a gasoline is isooctane, which has a density of 0.692 g/ml. What is the mass of 3.8 gal of the gasoline (1 gal = 3.78 l)?

sveticcg [70]

Density is the ratio of mass to the volume.

The mathematical expression is given as:

$density=\frac{mass}{volume}$

Now, density of isooctane = $0.692 g/mL$

Volume = $3.8 gal$

Since, 1 gallon = 3.78 L

So, 3.8 gal = $3.78 L\times 3.8$

= $14.364 L$

As, 1 L = 1000 mL

Therefore, $14.364 L$ = $14.364 L\times 1000 mL$

Volume in mL = $14364 mL$

Put the values,

$0.692 g/mL=\frac{mass}{14364 mL}$

$m = 0.692 g/mL\times 14364 mL$

= $9939.888 g$

Hence, mass of 3.8 gal of the gasoline is $9939.888 g$ .

6 0

2 years ago

The hydrochloride form of cocaine has a solubility of 1.00 g in 0.400 mL water. Calculate the molarity of a saturated solution o

Tanya [424]

Answer:

The molarity of the solution is 7.4 mol/L

Explanation:

From the question above

0.400 ml of water contains 1.00 g of hydrochloride form of cocaine

Therefore 1000 ml of water will contain x g of hydrochloride form of cocaine

x = 1000 / 0.400

x = 2500 g

2500g of hydrochloride form of cocaine is present in 1000 ml of water.

Mole of hydrochloride form of cocaine = mass /molar mass of hydrochloride

Mole of hydrochloride form of cocaine = 2500/339.8

= 7.4 mol

Molarity = mol/ volume in liter (L)

molarity = 7.4 /1

Molarity = 7.4 mol/L

6 0

3 years ago

Read 2 more answers

Pls help asap!!!!

AVprozaik [17]

Answer: The pressure of the He is 2.97 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

$p_{total}=p_{N_2}+p_{O_2}+p_{He}.$

Given : $p_{total}$ =total pressure of gases = 6.50 atm

$p_{N_2}$ = partial pressure of Nitrogen = 1.23 atm

$p_{O_2}$ = partial pressure of oxygen = 2.3 atm

$p_{He}$ = partial pressure of Helium = ?

putting in the values we get:

$6.50atm=1.23atm+2.3atm+p_{He}$

$p_{He}=2.97atm$

The pressure of the He is 2.97 atm

3 0

2 years ago

If an experiment with 10.2 g barium chloride produced 14.5 g silver chloride, calculate thr experimental mole ratio of silver ch

Leni [432]

The experimental mole ratio of silver chloride to barium chloride is calculated as below

fin the mole of each compound

mole= mass/molar mass
moles of AgCl = 14.5g/142.5 g/mol = 0.102 moles of AgCl
moles of BaCl2 = 10.2 g/208 g/mol = 0.049 moles of BaCl2

find the mole ratio by dividing each mole with the smallest mole(0.049)

AgCl= 0.102/0.049 =2
BaCl2 = 0.049/0.049 =1
therefore the mole ratio AgCl to BaCl2 is 2 :1

3 0

2 years ago

Read 2 more answers