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3 years ago

Germanium, Astatine, Tellurium, and Arsenic are all _____. metalloids non-metals metals noble gases

Chemistry

1 answer:

zmey [24]3 years ago

4 0

Answer:-

Metalloids

Explanation: -

Metalloids are elements with properties that are somewhat in between those that of metals and non metals. They have generally 4 or 5 electrons in their valence shell for up to the 4th period to be called a metalloid. From the fifth period 6 valence electrons can make an element metalloid.

From the sixth even 7 valence electrons can make an element metalloid

The electronic configuration of Germanium is

2,8,18, 4

So it is a metalloid.

The electronic configuration of tellurium,

2,8,18, 18, 6

So it is a metalloid.

The electronic configuration of Arsenic

2,8,18, 5

So it is a metalloid.

The electronic configuration of astatine

2,8,18, 32, 18, 7

So it is a metalloid.

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Why do atoms of nonmetals form anions? Support your answer with an example.

Papessa [141]

Nonmetals form negatively charged ions, or anions. They do this because they need to gain one to three electrons in order to achieve an octet of valence electrons, making them isoelectronic with the noble gas at the end of the period to which they belong.

5 0

3 years ago

How old is a bone if it now .3125 of C-14 when it originally had 80.0g of C-14

Taya2010 [7]

<h3>Answer:</h3>

42960 years

<h3>Explanation:</h3>

<u>We are given;</u>

Remaining mass of C-14 in a bone is 0.3125 g
Original mass of C-14 on the bone is 80.0 g
Half life of C-14 is 5370 years

We are required to determine the age of the bone;

Using the formula;

Remaining mass = Original mass × 0.5^n , where n is the number of half lives.

Therefore;

0.3125 g = 80.0 g × 0.5^n

3.90625 × 10^-3 = 0.5^n

Introducing logarithm on both sides;

log 3.90625 × 10^-3 = n log 0.5

Solving for n

n = log 3.90625 × 10^-3 ÷ log 0.5

= 8

Therefore, the number of half lives is 8
But, 1 half life is 5370 years
Therefore;

Age of the rock = 5370 years × 8

= 42960 years

Thus, the bone is 42960 years old

7 0

3 years ago

State Henry's law. Give an example of Henry's law.

ruslelena [56]

Answer:

Found this off of google, "Henry's law comes into play every time a bottle of Pepsi (or any other carbonated drink) is opened. The gas above the unopened carbonated drink is usually pure carbon dioxide, kept at a pressure which is slightly above the standard atmospheric pressure."

4 0

3 years ago

How can ionic compounds be neutral?

Rudiy27

If u seperate them into halves at a time

8 0

3 years ago

Please with this problem

olasank [31]

<h3>Answer:</h3>

Empirical Formula = C₃H₈O₃

Molecular Formula = C₃H₈O₃

<h3>Solution:</h3>

Data Given:

Mass of Sample = 9.2 g

Mass of Carbon = 3.6 g

Mass of Hydrogen = 0.8 g

Mass of Oxygen = 9.2 - (3.6 + 0.8) = 4.8 g

Step 1: Calculate Moles of each Element;

Moles of C = Mass of C ÷ At.Mass of C

Moles of C = 3.6 ÷ 12.01

Moles of C = 0.2997 mol

Moles of H = Mass of H ÷ At.Mass of H

Moles of H = 0.8 ÷ 1.01

Moles of H = 0.7920 mol

Moles of O = Mass of O ÷ At.Mass of O

Moles of O = 4.8 ÷ 16.0

Moles of O = 0.3000 mol

Step 2: Find out mole ratio and simplify it;

C H O

0.2997 0.7920 0.3000

0.2997/0.2997 0.7920/0.2997 0.3000/0.2997

1 2.64 1.001

Multiply by 3,

3 7.92 ≈ 8 3

Hence, Empirical Formula = C₃H₈O₃

Step 3: Calculating Molecular Formula:

Molecular formula is calculated by using following formula,

Molecular Formula = n × Empirical Formula ---- (1)

Also, n is given as,

n = Molecular Weight / Empirical Formula Weight

Molecular Weight = 92 g.mol⁻¹

Empirical Formula Weight = 12 (C₃) + 1.01 (H₈) + 16 (O₃) = 92.08 g.mol⁻¹

So,

n = 92 g.mol⁻¹ ÷ 92 g.mol⁻¹

n = 1

Putting Empirical Formula and value of "n" in equation 1,

Molecular Formula = 1 × C₃H₈O₃

Molecular Formula = C₃H₈O₃

7 0

3 years ago