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adell [148]
3 years ago
9

Advanced persistent threat (APT) attackers want to ________. Select one: a. create awareness for their causes b. remain unnotice

d so they can continue to steal data c. conduct cyberwarfare d. reveal weaknesses in business and government websites and then force them offline
Computers and Technology
1 answer:
Romashka [77]3 years ago
6 0

Answer:

Option b (remain unnoticed so they can continue to steal data) is the right approach.

Explanation:

  • APT seems to be sustained but instead designed to target coordinated attack whereby an attacker achieves network access including a longer length of time impossible to conceive.
  • Usually, APT assaults become targeted at organizations throughout fields including such national security, engineering, as well as the financial services industry, as they make increased-value details.

There are 3 other possibilities not relevant to just the given case. So that the option here was the right one.

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A user called to inform you that the laptop she purchased yesterday is malfunctioning and will not connect to her wireless netwo
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Answer:

B. Have the user press the appropriate function key combination to enable the wireless radio and then attempt to connect to the wireless network.

Explanation:

Every more often than not, users may experience wireless connection problems. How they respond to these issues solely depends on various factors. When a user like this has issues connecting to the network, first on the list of proper troubleshooting procedures is to check whether the wireless adapter or the function key that turns the wireless radio connection on is toggled on. Sometimes the most obvious causes are the hardest to see. The user should check this first because it will save him or her lots of troubleshooting time if the switch was simply physically disabled.

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3 years ago
Create a new Java project/class called ChangeUp. Create an empty int array of size 6. Create a method called populateArray that
-Dominant- [34]
<h2>Answer:</h2><h2></h2>

//import the Random and Scanner classes

import java.util.Random;

import java.util.Scanner;

//Begin class definition

public class ChangeUp {

   

   //Begin the main method

  public static void main(String args[]) {

       //Initialize the empty array of 6 elements

      int [] numbers = new int [6];

       

       //Call to the populateArray method

       populateArray(numbers);

       

       

   } //End of main method

   

   

   //Method to populate the array and print out the populated array

   //Parameter arr is the array to be populated

   public static void populateArray(int [] arr){

       

       //Create object of the Random class to generate the random index

       Random rand = new Random();

       

       //Create object of the Scanner class to read user's inputs

       Scanner input = new Scanner(System.in);

       

       //Initialize a counter variable to control the while loop

       int i = 0;

       

       //Begin the while loop. This loop runs as many times as the number of elements in the array - 6 in this case.

       while(i < arr.length){

           

           //generate random number using the Random object (rand) created above, and store in an int variable (randomNumber)

           int randomNumber = rand.nextInt(6);

       

           //(Optional) Print out a line for formatting purposes

           System.out.println();

           

           //prompt user to enter a value

           System.out.println("Enter a value " + (i + 1));

           

           //Receive the user input using the Scanner object(input) created earlier.

           //Store input in an int variable (inputNumber)

           int inputNumber = input.nextInt();

           

           

           //Store the value entered by the user in the array at the index specified by the random number

           arr[randomNumber] = inputNumber;

           

           

           //increment the counter by 1

          i++;

           

       }

       

       

       //(Optional) Print out a line for formatting purposes

       System.out.println();

       

       //(Optional) Print out a description text

      System.out.println("The populated array is : ");

       

       //Print out the array content using enhanced for loop

       //separating each element by a space

       for(int x: arr){

           System.out.print(x + " ");

       }

   

       

  } //End of populateArray method

   

   

   

} //End of class definition

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining the lines of the code.

This source code together with a sample output has been attached to this response.

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
0d7446bcb6b48f78b8adbfa3da89789c.png
3 0
3 years ago
Write a C++ programthat reads in the side of a square and prints out a pattern on$
AnnZ [28]

Answer:

#include<iostream>

using namespace std;

//main function

int main(){

   //initialize the variables

   int side;

   //print the message

   cout<<"Please enter the side of square: ";

   cin>>side;  //read the vale and store in the variable.

   // for loop

   for(int i=1;i<=side;i++){  //lop for rows

       for(int j=1;j<=side;j++){   //loop for column

           cout<<"$";  //print the '*'

       }

       cout<<endl;

   }

}

Explanation:

Create the main function and declare the variable side.

print the message on the screen for the user and then store value enter by the user on the variable side.

take the nested for loop for print the pattern.

nested for loop means, loop inside another loop it is used for print the pattern having rows and columns.

the first loop updates the row number and the second the loop print the character '$' in the column-wise.

in the code,

if i = 1, for loop check the condition 1 <= 5 if the value of side is assume 5.

condition is true and the program moves to the second for loop and starts to print the character '$' five times after that, print the new line.

then, the above process repeat for different rows and finally, we get the pattern in square shape.

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C... it’s c ok.......................
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