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3 years ago

What is the value of x?

Mathematics

1 answer:

Arisa [49]3 years ago

3 0

35+70 = 105
180-105 = 75
x = 75

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Verify that fand g are inverse functions (both questions please)

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Answer:

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2 years ago

What do u add to 5 4/7 to get 7

enot [183]

Answer:

10/7

Step-by-step explanation:

5 4/7=39/7

x+39/7=7

x=7-39/7

x=49/7-39/7

x=10/7

6 0

3 years ago

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Solve for the value of z.

Yuki888 [10]

z=18

3z+4+2z-4+90=180

5z+4-4+90=180

5z+90=180

5z=90

z=18

4 0

3 years ago

Show all work to factor x^4 − 5x^2 + 4 completely.

Mademuasel [1]

Answer:

(x+1) (x-1) (x+2) (x-2)

Step-by-step explanation:

Let u = x^2

= u^2 - 5u + 4

(Factor u^2 - 5u + 4)

= (u-1) (u-4)

Substitute back u = x^2

= (x^2 -1 ) (x^2 - 4)

Factor x^2 - 1 and x^2 -4

= (x+1) (x-1) (x+2) (x-2)

Hope this helped... :)

If you need to see the work for yourself, copy/paste this link

https://www.symbolab.com/solver/factor-calculator/factor%20x%5E%7B4%7D%20%E2%88%92%205x%5E%7B2%7D%20%2B%204%20

3 0

3 years ago

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What is x, the distance between points A and A'? 2. 4 units 4. 8 units 13. 6 units 14. 4 units.

adelina 88 [10]

The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

Given that,

The points A (3, -5) and A' (2, -3).

We have to determine,

The distance between point A and A'.

According to the question,

The distance between two points is determined by using the distance formula.

$\rm Distance \ formula = \sqrt{(x_2-x_2) ^2+ (y_2-y_2)^2$

Then,

The distance between points A (3, -5) and A' (2, -3) is,

$\rm Distance = \sqrt{(2-3) ^2+ ((-3)-(-5))^2}\\\\ Distance = \sqrt{(-1) ^2+ (2)^2}\\\\ Distance = \sqrt{1+4}\\\\Distance = \sqrt{5}\\\\Distance = 2.4 \ units$

Hence, The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

For more details refer to the link given below.

brainly.com/question/8069952

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2 years ago

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