We have that
x² − 8xy + y²<span> = 8
</span>2x-8y-8x(dy/dx)+2y*(<span>dy/dx)=0
</span>8x(dy/dx)-2y*(dy/dx)=2x-8y
[8x-2y]*(dy/dx)=2x-8y
(dy/dx)=[2x-8y]/[8x-2y]
(dy/dx)=2*[x-4y]/2*[4x-y]
(dy/dx)=[x-4y]/[4x-y]
the answer is
(dy/dx)=[x-4y]/[4x-y]
First find the time that the ball is level with the top of the building on its descent. You can do this by solving 280 = -16^2 + 48t + 280 for t. This gives t = 3 seconds .
Then when the ball reaches the ground the time t is obtained by solving 0 = -16t^2 + 48t + 280 This gives t = 5.94 seconds.
Answer in interval notation is (3, 5.94].
First, we have to solve for x by isolating it on one side.
6x + 10 = -8
(Subtract 10 from both sides)
6x = -18
(Divide both sides by 6)
x = -3
On option C, x is on -3, so that would be the correct answer
Answer:
54 degrees
Step-by-step explanation:
