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Juliette [100K]
3 years ago
11

Hellpppppppp plzzzz thank youuuu

Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer:

< 2 and < 3 are complementary

Step-by-step explanation:

< 2 and < 3 are complementary because since 1 and 2 are complementary and 1 is congruent to 3 that would mean that 1 and 3 are equal degrees, so you could replace one with 2 as shown here: < 1 and < 2 are complementary and < 1 is congruent to < 3, then < 2 and < 3 are complementary. Assume < 1, < 2, and < 3 do not equal 45 degrees.

Please mark as brainliest! Hope this helps! Just ask if you need anymore help!

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Arjun solved the equation 7·m=56 His work is shown. What error did Arjun make?
natulia [17]
He multiplied rather than dividing.

\mathrm{Divide\:both\:sides\:by\:}7 \ \textgreater \  \frac{7m}{7}=\frac{56}{7} \ \textgreater \  Simplify \ \textgreater \ m = 8

Hope this helps!
6 0
2 years ago
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In the year 2008, a person bought a new car for $26500. For each consecutive year
DanielleElmas [232]

Answer:

$20500

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26500-(.12*26500)=23320 For 1 year

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6 0
2 years ago
What is the average of -30 -15 -20 55
defon

Answer:

-2.5

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8 0
2 years ago
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Given the equation square root of quantity 2x plus 8 end quantity equals 6, solve for x and identify if it is an extraneous solu
Alex_Xolod [135]

Answer:

Solution: x = 6

Step-by-step explanation:

Given equation is:

\sqrt{2x+8}=6

In order to solve the equation both sides will be squared

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Verifying the solution

\sqrt{2(14)+8} = 6\\ \sqrt{28+8} = 6\\\sqrt{36} = 6\\6 = 6

3 0
2 years ago
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Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m
laila [671]
Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of t_{ \frac{1}{2} } after t years is given by

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Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

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Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>
5 0
3 years ago
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