The vertex form of the equation y = -x^2 + 4x - 1 is y = -(x - 2)^2 + 3
<h3>How to determine the vertex form of the quadratic equation?</h3>
The quadratic equation is given as:
y = -x^2 + 4x - 1
Differentiate the above quadratic equation.
This is done with respect to x by first derivative
So, we have:
y' = -2x + 4
Set the derivative to 0
-2x + 4 = 0
Subtract 4 from both sides of the equation
-2x + 4 - 4 = 0 - 4
Evaluate the difference in the above equation
-2x = -4
Divide both sides of the above equation by -2
x = 2
Rewrite as
h = 2
Substitute 2 for x in the equation y = -x^2 + 4x - 1
y = -2^2 + 4 *2 - 1
Evaluate the equation
y = 3
Rewrite as:
k = 3
A quadratic equation in vertex form is represented as:
y = a(x - h)^2 + k
So, we have:
y = a(x - 2)^2 + 3
In the equation y = -x^2 + 4x - 1, a = -1
So, we have:
y = -(x - 2)^2 + 3
Hence, the vertex form of the equation y = -x^2 + 4x - 1 is y = -(x - 2)^2 + 3
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Answer:
0.98
Step-by-step explanation:
13.04-12.06=0.98
Answer:
A) $11
Step-by-step explanation:
I took the test, hope this helps
Answer:
Hello, There!
<h2>Question</h2>
There is a special relationship between the lengths of the legs of a right triangle and the length of its hypotenuse. This relationship is known as the
<h2>Answer</h2>
Pythagorean Theorem.
Step-by-step explanation:
The Pythagorean Theorem states that the square of one leg (a) plus the square of the other leg (b) is equal to the square of the hypotenuse (c). This can be written as + = .