2 years ago

Classify two dimensional figures question 4

Mathematics

1 answer:

poizon [28]2 years ago

7 0

Answer:

A. All sides with the equal length.

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The area of the rectangular floor in Tamara's room is 95 5/6 square

White raven [17]

Area of rectangle is width × length
which means area of rectangular floor in Tamara's room = width of room × length of room
-> 95 ⅚ sq feet = 8 ⅓ feet × length of
->(95 + 5/6) sq feet = (8 + 1/3) feet × length of room
->575/6 sq feet = 25/3 feet × length of room
length of room = (575/6)/(25/3)
= 575 × 3/6 × 25)
= 23/2
= 11 ½ feet

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Solve the system algebraically.<br> 3x - 2y - 1 = 0 y = 5x + 4 <br> What is the solution?

Bogdan [553]

Answer:

$x=\frac{-9}{7}$

$y=\frac{-17}{7}$

Step-by-step explanation:

We have been given the equation:

$3x-2y-1=0$

And $y=5x+4$

Second equation can be rewritten as:

$5x-y=-4$

We will solve the equations:

$3x-2y=1$ (1)

$5x-y=-4$ (2)

Multiply equation (1) by 5 and equation (2) by 3 we get:

$15x-10y=5$ (3)

$15x-3y=-12$ (4)

Now, subtract (4) from (3) we get:

$-7y=17$

$y=\frac{-17}{7}$

Now substitute $y=\frac{-17}{7}$ in equation (1) we get:

$3x-2{\frac{-17}{7}}=1$

$3x+\frac{34}{7}=1$

$21x=-27$

$x=\frac[-27}{21}$

$x=\frac{-9}{7}$

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2 years ago

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2x-4y=2 -2x+3y=0 elimination

statuscvo [17]

$2x-4y=2 \\
\underline{-2x+3y=0} \\
-4y+3y=2+0 \\
-y=2 \\
y=-2 \\ \\
2x-4y=2 \\
2x-4 \times (-2)=2 \\
2x+8=2 \\
2x=2-8 \\
2x=-6 \\
x=\frac{-6}{2} \\
x=-3 \\ \\
(x,y)=(-3,-2)$

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3 years ago

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