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Amanda [17]
4 years ago
5

How many milliliters of a 3.0 M HCL solution are required to make 250.0 milliliters of 1.2 M HCL

Chemistry
1 answer:
tiny-mole [99]4 years ago
5 0
You can use M x V = M' x V'

3 x V = 250 x 1.2

V = 100 ml
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Answer:

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HTart⁻  +  H₂O  ⇄  H₃O⁺   +  Tart⁻²           Ka2

When we anaylse the base, we have

Tart⁻²   +  H₂O  ⇄  OH⁻  +  HTart⁻       Kb1

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Remember that Ka1 . Kb2  = Kw, plus pKa1 + pKb2 = 14

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