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3 years ago

How many milliliters of a 3.0 M HCL solution are required to make 250.0 milliliters of 1.2 M HCL

Chemistry

1 answer:

tiny-mole [99]3 years ago

5 0

You can use M x V = M' x V'

3 x V = 250 x 1.2

V = 100 ml

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Andi performs the calculation that is shown below.

rodikova [14]

Answer: 3.59

Explanation:

(2.06)(1.743)(1.00)

2.06 × 1.743 × 1.00

= 3.59058

Two of the multiplied digits are represented in 3 significant figures. Therefore, for correct representation, the result of the product should be written to three significant figures.

3.59058 to 3 significant figures:

First three digits = 3.59

Fourth digit '0' is less than 5, and thus rounded to 0 with other succeeding digits

Therefore, (2.06)(1.743)(1.00) to 3 significant figures equals :

3.59

3 0

3 years ago

Advanced flow measuring devices ? <br> I need info about this topic please

Elenna [48]

Answer:

they are:-

venturi meter.

orfice plate.

Dall tube .

pitot tube.

Averaging pitot tube .

cone meter.

linear resis meter.

5 0

2 years ago

Gasoline and kerosene (specific gravity 0.820) are blended to obtain a mixture with a specific gravity of 0.770. Calculate the v

Dmitrij [34]

Answer:

The volumetric ratio is 0,71

Explanation:

Let's begin with the equation:

$Db = Mb/Vb$ (1)

Where:

Db: Blend Density, Mb: Blend Mass and Vb: Blend Volume

And we know: $Vb = Vg + Vk$ (2)

Where:

Vg: Gasoline Volume and Vk: Kerosene Volume

Therefore replacing (2) into (1):

$Db = (Mg + Mk) / (Vg + Vk)$

$Db = (Dg * Vg + Dk * Vk)/(Vg + Vk)$ (3)

Where:

Dg: Gasoline Density and Dk: Kerosene Density

The specific gravity is defined as:

$SG = Substance Density / Reference Density$

Therefore:

$Db = SGb * Dref\\Dg = SGg * Dref\\Dk = SGk * Dref$

Where:

Dref: Reference Density

SGb: Blend Specific Gravity

SGg: Gasoline Specific Gravity (which is 0.7 approximately)

SGk: Kerosene Specific Gravity

Replacing these equations into (3) we get:

$SGb * Dref = (SGg * Dref * Vg + SGk * Dref * Vk)/(Vg + Vk)$

$SGb * Dref = Dref * (SGg * Vg + SGk * Vk)/(Vg + Vk)$

$SGb = (SGg * Vg + SGk * Vk)/(Vg + Vk)$

$SGb * (Vg + Vk) = SGg * Vg + SGk * Vk$

$SGb * Vg + SGb* Vk = SGg * Vg + SGk * Vk$

Replacing with the Specific Gravity data, we obtain:

$0.77 * Vg + 0.77 * Vk = 0.7 * Vg + 0.82 * Vk$

$0.77 * Vg - 0.7 * Vg = 0.82 * Vk - 0.77 * Vk$

$0.07 * Vg = 0.05 * Vk$

$Vg/Vk = 0.05/0.07$

$Vg/Vk = 0.71$

8 0

2 years ago

Which of the following latitudes receive the most direct solar energy?

Misha Larkins [42]

Answer:

The answer to your question is D.

Explanation:

The latitudes near the equator receives the most direct solar energy.

Hope this helps :)

8 0

3 years ago

The sun's inner core is the hottest part of the sun<br><br> true or false

harkovskaia [24]

False heat rises upwards therefore the hottest part of the sun would be upwards

3 0

3 years ago

Read 2 more answers