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Lyrx [107]
3 years ago
12

Based on these data, what is the average atomic mass of element b? 10.01 10.51 10.81 11.01

Chemistry
2 answers:
Agata [3.3K]3 years ago
6 0
Im pretty sure it is C
Lelechka [254]3 years ago
5 0
The right answer is C. 10.81
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describe in terms of ions, what happens during a neutralisation reaction- include the ionic equation for the formation of water
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Basically, the hydrogen and oxygen react forming  the liquid substance we all now know as WATER<span />
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3 years ago
7. Which subatomic particle was discovered first?
ki77a [65]

Answer: electron

Explanation:

6 0
3 years ago
Give the ion symbol for the ion that has 27 protons and 24 electrons.
Natalija [7]

Answer:

Z³⁺

Explanation:

The ion symbol can be depicted as Z³⁺ .

In this atom, the number of protons is 27 and the number of electrons is 24.

Protons are the positively charged particles within an atom.

Electrons are the negatively charged particles within an atom.

 To find the charge;

   Charge  = Number of protons  - number of electrons

  Charge  = 27   - 24  = +3

The atom is positively charged and it can be depicted as Z³⁺

7 0
3 years ago
Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
Phoenix [80]

Answer:

pH = 8.0

Explanation:

First, we have to calculate the moles of NaOH.

35.8 \times 10^{-3}L.\frac{0.020mol}{L} =7.2\times 10^{-4}mol

Let's consider the balanced equation.

C₂H₄O₃ + NaOH ⇒ C₂H₃O₃Na + H₂O

The molar ratio C₂H₄O₃: NaOH: C₂H₃O₃Na is 1: 1: 1. So, when 7.2 × 10⁻⁴ moles of NaOH react completely with 7.2 × 10⁻⁴ moles of C₂H₄O₃ they form 7.2 × 10⁻⁴ moles of C₂H₃O₃Na.

The concentration of C₂H₃O₃Na is:

\frac{7.2\times 10^{-4}mol}{60.8 \times 10^{-3}L} =0.012M

C₂H₃O₃Na dissociates according to the following equation:

C₂H₃O₃Na(aq) ⇒ C₂H₃O₃⁻(aq) + Na⁺(aq)

C₂H₃O₃⁻ comes from a weak acid so it undergoes basic hydrolisis.

C₂H₃O₃⁻ + H₂O ⇄ C₂H₄O₃ + OH⁻

If we know that pKa for C₂H₄O₃ is 3.9, we can calculate pKb for C₂H₃O₃⁻ using the following expression:

pKa + pKb = 14

pKb = 14 -3.9 = 10.1

10.1 = -log Kb

Kb = 7.9 × 10⁻¹¹

We can calculate [OH⁻] using the following expression:

[OH⁻] = √(Kb.Cb)               <em>where Cb is the initial concentration of the base</em>

[OH⁻] = √(7.9 × 10⁻¹¹ × 0.012M) = 9.7 × 10⁻⁷ M

Now, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log (9.7 × 10⁻⁷) = 6.0

pH + pOH = 14

pH = 14 - pOH = 14 - 6.0 = 8.0

7 0
3 years ago
I need help ASAP! 10 points!
Nina [5.8K]

Answer:

The answer to this question is ( a )

Explanation:

7 0
3 years ago
Read 2 more answers
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