Answer:
In the parallel plate capacitor,
q = e0EA, q is the charge on the plate, E is electric field intensity, A is the area of each plate, e0 = 8.854 x 10^-12F/m.
The charge density is q/A(charge per unit area)
q/A = e0 x E, from the equation above.
Therefore, q/A = 1.40 x 10^4V/m x 8.854 x 10^-12F/m
q/A = 12.3956 x 10^-8 = 1.23956 x 10^-7C/m2
Explanation:
A parallel plate capacitor consist of two plates facing eachother with separation d in between them. One of the plate is positively charged and the other is negatively charged. There is a dielectric material in between the plates. The charges on the plate is given as: q = e0EA
Answer:
Your missing the entire Transitional Metal group as well as all the Lanthanides and Actinides.
Explanation:
The groups are:
Alkali metals.
Alkaline earth metals.
Transitional metals.
Crystallogens.
Pnictogens.
Chalcogens.
Halogens.
Noble gases.
Answer:
1. They will react.
2. 2HCI + Zn —> ZnCl2 + H2
Explanation:
1. From the question given above,
We can see that Zn is higher than H in the activity series.
NOTE: Elements higher (i.e at the top) in the activity series will displace those lower (i.e at the bottom) in the series. Thus, Zn is higher in the series than H. Therefore, Zn will displace H from solution. Hence, they will react.
2. The product obtained from the reaction can be seen as follow:
HCI + Zn —> ZnCl2 + H2
The above equation can be balance as follow:
There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:
2HCI + Zn —> ZnCl2 + H2