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2 years ago

Read the scenario.

Chemistry

2 answers:

stich3 [128]2 years ago

8 0

Answer : The balanced chemical reaction will be:

$2H_2+O_2\rightarrow 2H_2O$

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

If the amount of atoms of each type on the left and right sides of a reaction differs then to balance the equation by adding coefficient in the front of the elements or molecule or compound in the chemical equation.

The coefficient tell us about that how many molecules or atoms present in the chemical equation.

As per question, when 2 molecules of hydrogen gas and 1 molecule of oxygen gas react to yield 2 molecules of water.

The balanced chemical reaction will be:

$2H_2+O_2\rightarrow 2H_2O$

irakobra [83]2 years ago

5 0

2H2+O2→2H2O
We have to be aware that the number of atoms are the same on both reactant side and product side.

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Reliable results are results that can be... A: Communicated

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A 10.0 g sample of an unknown liquid is vaporized at 120.0°C and 5.0 atm. The volume of the vapour is found to be 568.0 mL. The

Minchanka [31]

Answer:

molecular formula of liquid = C₈H₁₈

Explanation:

First we determine the empirical formula of the liquid:

Number of moles of each element present in the liquid = % mass / molar mass

For Carbon, (molar mass = 12.01 g/mol) : 84.2/12.01 =7.011 moles

For Hydrogen (molar mass = 1.01 g/mol) : 15.8/1.01 = 15.643

Simplest mole ratio of the elements, C : H is given by:

C = 7.011/7.011 = 1.0

H = 15.643/7.011 = 2.23

Multiplying through with 5, C:H = 5:11

Therefore, empirical formula is C₅H₁₁

The molecular mass of the liquid is next determined:

Using PV = nRT to find the number of moles of the liquid present

P = 5.0 atm; V = 568.0 mL = 0.568 L; R = 0.082 L*atmmol⁻¹ K⁻¹; T = 273 + 120 = 393 K

n = PV/RT = (5*0.568)/0.082*393

n = 0.088 moles

Molar mass of liquid = mass/no of moles = 10.0 g/ 0.088 moles = 113.63 gmol⁻¹

Molecular formula = n(empirical formula)

Molar mass of empirical formula, C₅H₁₁ = 71 gmol⁻¹

n = molecular mass/empirical mass = 113.63/71 = 1.6

Therefore, molecular formula = 1.6*(C₅H₁₁) = C₈H₁₈

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2 years ago

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PbSO₄(s) ⇄ Pb²⁺(aq) + SO₄²⁻(aq)
Initial - -
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Equilibrium X X

Ksp = [Pb²⁺(aq)] [SO₄²⁻(aq)]
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1.6 x 10⁻⁸ = X²
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Hence the Pb²⁺ concentration in underground water is 1.3 x 10⁻⁴ M.
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3 years ago

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Answer:

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