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Klio2033 [76]
3 years ago
14

Read the scenario.

Chemistry
2 answers:
stich3 [128]3 years ago
8 0

Answer : The balanced chemical reaction will be:

2H_2+O_2\rightarrow 2H_2O

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

If the amount of atoms of each type on the left and right sides of a reaction differs then to balance the equation by adding coefficient in the front of the elements or molecule or compound in the chemical equation.

The coefficient tell us about that how many molecules or atoms present in the chemical equation.

As per question, when 2 molecules of hydrogen gas and 1 molecule of oxygen gas react to yield 2 molecules of water.

The balanced chemical reaction will be:

2H_2+O_2\rightarrow 2H_2O

irakobra [83]3 years ago
5 0
2H2+O2→2H2O
We have to be aware that the number of atoms are the same on both reactant side and product side.
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A solution is made using 200.0 mL of methanol (density 0.792 g/mL) and 985.1 mL of water (density 1.000 g/mL). What is the mass
DaniilM [7]

<u>Answer:</u> The mass percent of methanol in solution is 13.85 %

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

  • <u>For water:</u>

Density of water = 1.000 g/mL

Volume of water = 985.1 mL

Putting values in above equation, we get:

1.000g/mL=\frac{\text{Mass of water}}{985.1mL}\\\\\text{Mass of water}=(1.000g/mL\times 985.1mL)=985.1g

  • <u>For methanol:</u>

Density of methanol = 0.792 g/mL

Volume of methanol = 200.0 mL

Putting values in above equation, we get:

0.792g/mL=\frac{\text{Mass of methanol}}{200.0mL}\\\\\text{Mass of methanol}=(0.792g/mL\times 200.0mL)=158.4g

To calculate the mass percent of methanol, we use the equation:

\text{Mass percent of methanol}=\frac{\text{Mass of methanol}}{\text{Mass of solution}}\times 100

Mass of solution = [158.4 + 985.1] g = 1143.5 g

Mass of methanol = 158.4 g

Putting values in above equation, we get:

\text{Mass percent of methanol}=\frac{158.4g}{1143.5g}\times 100=13.85\%

Hence, the mass percent of methanol in solution is 13.85 %

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zheka24 [161]

Answer: A

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Since there's no "?" shown in the equation, let's balance it and solve it entirely.

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