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Gwar [14]
2 years ago
12

When developing an experimental design, which action would improve the

Chemistry
1 answer:
11111nata11111 [884]2 years ago
4 0

Answer:

A

Explanation:

I'm right I took the test

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Calculate the molar mass of CH4 gas at STP when 5.46Lof the gas weighs 4g??​
meriva

Answer:

About 16.42 grams

Explanation:

PV=nRT \\\\(1)(5.46L)=n(0.0821)(273) \\\\n\approx 0.2436 \\\\4g/0.2436\approx 16.42

Hope this helps!

6 0
3 years ago
Where are atoms located? (check all that apply)*
Jobisdone [24]
I think it’s 2 hope that helped
4 0
3 years ago
What is the concentration (m) of sodium ions in 4.57 l of<br> a.847 m na3p solution?
drek231 [11]
A group of environmentalists were discussing the benefits and drawbacks associated with using fossil fuels. Which argument <span>best </span>fits the conversation? 
Fossil fuels are cheaper than alternative forms of energy.Fossil fuel reserves will never be depleted.<span>Fossil fuels are easily renewed. </span><span>Fossil fuel use does not affect the environment.</span>
8 0
3 years ago
How do you find a theoretical mass? Is there a difference between theoretical mass and theoretical yield?
swat32

Theoretical yield is the quantity of a product obtained from the complete conversion of the limiting reactant in a chemical reaction. It is the amount of product resulting from a perfect chemical reaction and thus not the same as the amount you'll actually get from a reaction.

3 0
4 years ago
A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 26.6
joja [24]

<u>Answer:</u> The concentration of CH_3COOH comes out to be 0.16 M.

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is CH_3COOH

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=25mL\\n_2=1\\M_2=0.175M\\V_2=26.6mL

Putting values in above equation, we get:

1\times M_1\times 25=1\times 0.175\times 26.6\\\\M_1=0.1862M

Hence, the concentration of CH_3COOH comes out to be 0.1862 M.

4 0
3 years ago
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