A 3-kilogram bag of oranges costs $9.87. What is the unit price?

The ______________ probability of an outcome is obtained by dividing the frequency of occurrence of an event by the number of tr

Norma-Jean [14]

Answer:

Empirical probability

Step-by-step explanation:

Empirical probability is data collected from experiment and real-life situation.

The "empirical probability" of an outcome is obtained by dividing the frequency of occurrence of an event by the number of trails of the experiment.

$\Longrightarrow: \sf{P(E)=\dfrac{\text{number of times event occured}}{\text{number of trails}}$

Therefore, the correct answer is empirical probability.

I hope this helps you! Let me know if my answer is wrong or not.

3 0

2 years ago

Simplify this pleasee

DochEvi [55]

Answer:

48

Step-by-step explanation:

3(4)^2

48 is your answer 

5 0

3 years ago

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is a separable differential equation. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$

Therefore,

$\frac{1}{r} \ln |rA+P| = t+c$

Multiply both sides by $r.$

$\ln |rA+P| = rt+c_1, \quad c_1 := rc$

By taking exponents, we obtain

$e^{\ln |rA+P|} = e^{rt+c_1} \implies |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}$

Isolate $A$ .

$rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}$

Since $A = 0$ when $t=0$ , we obtain an initial condition $A(0) = 0$ .

We can use it to find the numeric value of the constant $c$ .

Substituting $0$ for $A$ and $t$ in the equation gives

$0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P$

Therefore, the solution of the given differential equation is

$A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)$

4 0

3 years ago

572000 square miles rounded ro the nearest hundred thousand

baherus [9]

It would be rounding it to 600000 because 600000 is the closest 100000x amount where x is an integer. I hope this helped and if I am right could I have brainliest? :)

7 0

3 years ago

What point is located at (1,-2)?

guapka [62]

Answer:

At point A

Step-by-step explanation:

As the x axis has -2 and y axis has 1

They are present in second quadrant

so (-1,2) is in point A

6 0

1 year ago