Answer:
![[6\frac{1}{6},6\frac{1}{3},6\frac{1}{2},6\frac{2}{3},6\frac{5}{6}]](https://tex.z-dn.net/?f=%5B6%5Cfrac%7B1%7D%7B6%7D%2C6%5Cfrac%7B1%7D%7B3%7D%2C6%5Cfrac%7B1%7D%7B2%7D%2C6%5Cfrac%7B2%7D%7B3%7D%2C6%5Cfrac%7B5%7D%7B6%7D%5D)
Step-by-step explanation:
we have the compound inequality

where
x is a mixed number
so
The solution for the compound inequality are the numbers
![[6\frac{1}{6},6\frac{2}{6},6\frac{3}{6},6\frac{4}{6},6\frac{5}{6}]](https://tex.z-dn.net/?f=%5B6%5Cfrac%7B1%7D%7B6%7D%2C6%5Cfrac%7B2%7D%7B6%7D%2C6%5Cfrac%7B3%7D%7B6%7D%2C6%5Cfrac%7B4%7D%7B6%7D%2C6%5Cfrac%7B5%7D%7B6%7D%5D)
Simplify the numbers
![[6\frac{1}{6},6\frac{1}{3},6\frac{1}{2},6\frac{2}{3},6\frac{5}{6}]](https://tex.z-dn.net/?f=%5B6%5Cfrac%7B1%7D%7B6%7D%2C6%5Cfrac%7B1%7D%7B3%7D%2C6%5Cfrac%7B1%7D%7B2%7D%2C6%5Cfrac%7B2%7D%7B3%7D%2C6%5Cfrac%7B5%7D%7B6%7D%5D)
The original price is c. Then the grocery bill will be: c - 0.05c = 0.95 c. You can also say since the beggining that 5% disscount implies 0.95 factor, which leads to c * 0.95 = 0.95c. Sorry if it’s wrong
Answer:
I think: 0 = 3x + b or b = -3x + 0 or x = -b + 0/3 or 3 = -b + 0/x
Sorry if you get this wrong..
Let us denote the number of tiles by

.
In the first store, if Darin bought

tiles, he would need to spend:

(measured in $)
In the second store, if Darin bought

tiles, he would need to spend:

(measured in $)
For the cost to be the same at both stores, it means (measured in $)

Moving

over to the left hand side and changing signs:

tiles
Let's check. If he buys 60 tiles in the first store, he spends:
$0.79×60 + $24 = $47.40 + $24 = $71.40
If he buys 60 tiles in the second store, he spends:
$1.19×60 = $71.40
∴
Darin needs to buy 60 tiles for the cost to be the same at both stores.
1 quart = 32 ounces
3 quarts = 96 ounces
96 ounces / 16 players = 6 ounces per player