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laila [671]
3 years ago
8

For the equation 3(2x − 5) = 6x + k, which value of k will create an equation with infinitely many solutions?

Mathematics
1 answer:
WINSTONCH [101]3 years ago
3 0

Answer:

3(2x-5)=6x+k

6x-15=6x+k

6x-6x=k+15

0=k+15

k=-15

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Step 1: Write equation

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Step 2: Solve for <em>x</em>

<u>Distribute:</u> -4x - 4 - 3 = -3x + 12

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Step by step explanation
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<h2>your answer is like this</h2>

Step-by-step explanation:

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aksik [14]
Remember
(a^b)^c=a^{bc}
and
\frac{x^a}{x^b}=x^{a-b}


so

\frac{(7^2)^5}{7^{-6}}=
\frac{7^{2*5}}{7^{-6}}=
\frac{7^{10}}{7^{-6}}=
7^{10-(-6)}=
7^{10+6}=
7^{16}

the answer is D
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