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DochEvi [55]
3 years ago
10

Help me please it’s all due soon

Chemistry
2 answers:
trapecia [35]3 years ago
7 0

Omg we did this but i forgot how to do it oh and i failed the test so um try to type the same problem on google that's how i got all the right answer on my homework. Watch this video tells you the answer https://youtu.be/S8GjkD296gg

taurus [48]3 years ago
5 0
1,2,1,2. Fill the number in in order
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5

Explanation:

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Electrons are valence and free moving so they take place in charge transfer
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The figure above shows the basic concepts of cell division
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A. DNA is copied. 
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6 0
3 years ago
In the following reaction, what is the effect on the direction of the reaction if more SO3 is added to the reaction mixture?
Stolb23 [73]

Answer:

The equilibrium shifts to produce more reactants.

Explanation:

According to the Le- Chatelier principle,

At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.

The equilibrium can be disturb,

By changing the concentration

By changing the volume

By changing the pressure

By changing the temperature

Consider the following chemical reaction.

Chemical reaction:

2SO₂ +  O₂  ⇄  2SO₃

In this reaction the equilibrium is disturb by increasing the concentration of Product.

When the concentration of product is increased the system will proceed in backward direction in order to regain the equilibrium. Because when product concentration is high it means reaction is not on equilibrium state. As the concentration of SO₃  increased the reaction proceed in backward direction to regain the equilibrium state and more reactant is formed.

3 0
3 years ago
What is the ph of a solution of 1.699 l of 1.25 m hcn, ka = 6.2 x 10-10, and 1.37 moles of nacn?
BlackZzzverrR [31]

The pH of a solution is 9.02.

c(HCN) = 1.25 M; concentration of the cyanide acid

n(NaCN) = 1.37 mol; amount of the salt

V = 1.699 l; volume of the solution

c(NaCN) = 1.37 mol ÷ 1.699 l

c(NaCN) = 0.806 M; concentration of the salt

Ka = 6.2 × 10⁻¹⁰; acid constant

pKa = -logKa

pKa = - log (6.2 × 10⁻¹⁰)

pKa = 9.21

Henderson–Hasselbalch equation for the buffer solution:

pH = pKa + log(cs/ck)

pH = pKa + log(cs/ck)

pH = 9.21 + log (0.806M/1.25M)

pH = 9.21 - 0.19

pH = 9.02; potential of hydrogen

More about buffer: brainly.com/question/4177791

#SPJ4

8 0
1 year ago
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