Electronic configuration: The distribution or arrangement of electrons of a molecule or an atom in molecular or atomic orbitals.
Ground state electron configuration: The distribution of electrons of an atom or molecule around the nucleus with lower levels of energy.
Now, 
stands for Ruthenium with atomic number 44. It is a metal and thus, has ability to lose electrons and, becomes positively charged ion.
One can write the electronic configuration with the help of atomic number and Afbau principle, Pauli exclusion principle etc.
Ground electronic Configuration is as follows:
Soft Hand notation: ![[Kr]4d^{7}5s^{1}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B7%7D5s%5E%7B1%7D)
Now, when ruthenium loses two electrons then it becomes 
, thus electron configuration becomes
Soft Hand notation: ![[Kr]4d^{6}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B6%7D)
The ground state electronic configuration of Ruthenium is and when it loses two electrons, then electronic configuration becomes ( )
Answer:
Option 5. 179L
Explanation:
The reaction is:
2 HCl + Na₂CO₃ → 2NaCl + H₂O + CO₂
The amount of collected CO₂ is 8 moles.
We apply the Ideal Gases Law at STP
STP are 1 atm of pressure and 273K of T°
P . V = n . R . T
1atm . V = 8 mol .0.082L.atm/mol.K . 273K
V = (8 mol .0.082L.atm/mol.K . 273K) / 1 atm = 179 L
B. examining the number of chromosomes in population
Since the addition of the H2O in the last step of hydroboration is anti-Markovnikov, the starting material is 1-pentyne.
The addition of H2 to C5H8 yields an alkene when a Lindlar catalyst is used. Recall that the Lindlar catalysts poisons the process so that the addition do not go on to produce an alkane.
When hydroboration is carried out on the alkene, we are told that a primary alcohol was obtained. We must note that in the last step of hydroboration, water is added in an anti- Markovnikov manner to yield the primary alcohol. Hence, the starting material must be 1-pentyne as shown in the image attached.
Learn more: brainly.com/question/2510654
