Answer:
% yield = 62.21 %
Explanation:
- C2H4(g) + H2O(l) → C2H6O(l)
∴ mass C2H4(g) = 4.6 g
∴ mass C2H6O(l) = 4.7 g
- % yield = ((real yield)/(theoretical yield))×100
theretical yield:
∴ molar mass C2H4(g) = 28.05 g/mol
⇒ mol C2H4(g) = (4.6 g)*(mol/28.05 g) = 0.164 mol
⇒ mol C2H6O(l) = (0.164 mol C2H4)*(mol C2H6O(l)/molC2H4(g))
⇒ mol C2H6O(l) = 0.164 mol
∴ molar mass C2H6O(l) = 46.07 g/mol
⇒ mass C2H6O(l) = (0.164 mol)*(46.07 g/mol) = 7.55 g
⇒ theoretical yield = 7.55 g
⇒ % yield = (4.7 g)/(7.55 g))*100
⇒ % yield = 62.21 %
Answer:
4 moles
Explanation:
The balanced equation for the reaction is given below:
N2 + 3H2 → 2NH3
From the balanced equation above,
1 mole of N2 produced 2 moles of NH3.
Therefore, 2 moles of N2 will produce = 2x2 = 4 moles of NH3.
Therefore, if we start with 2 moles of N2, then, we will produce 4 moles of NH3
Chemical change: is any change the results formation of new chemical substances
Physical changes: rearranged molecules but affect internal structures
