Question

Write a program that reads in a list of numbers, and for each number, determines and prints out whether or not that number is abundant.

Answer 1

int IsAbundant(int n)
{
int divisorSum = 0;
for (int i = 1; i < n; i++) {
 if ((n % i) == 0) {
  divisorSum += i;
 }
}
return divisorSum > n;
}


int main()
{
int number = 0;
do {
 printf("Enter a number (0 to quit): ");
 scanf_s("%d", &number);
 if (IsAbundant(number)) {
  printf("%d is abundant!\n", number);
   } else
   {
    printf("%d is not abundant.\n", number); }
   } while (number > 0);

   return 0;
}