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Genrish500 [490]
4 years ago
7

Write a program that reads in a list of numbers, and for each number, determines and prints out whether or not that number is ab

undant.
Computers and Technology
1 answer:
adelina 88 [10]4 years ago
7 0
int IsAbundant(int n)
{
int divisorSum = 0;
for (int i = 1; i < n; i++) {
 if ((n % i) == 0) {
  divisorSum += i;
 }
}
return divisorSum > n;
}


int main()
{
int number = 0;
do {
 printf("Enter a number (0 to quit): ");
 scanf_s("%d", &number);
 if (IsAbundant(number)) {
  printf("%d is abundant!\n", number);
   } else
   {
    printf("%d is not abundant.\n", number); }
   } while (number > 0);

   return 0;
}

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<h2>Answer:</h2><h2></h2>

//import the Random and Scanner classes

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  } //End of populateArray method

   

   

   

} //End of class definition

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining the lines of the code.

This source code together with a sample output has been attached to this response.

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
0d7446bcb6b48f78b8adbfa3da89789c.png
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