Ask question

Ask question

All categories

3 years ago

13

Please help! when 2 fractions refer to the same whole, explain why the fraction with a lesser denominator has larger pieces than

the fraction with a greater denominator.

1 answer:

tresset_1 [31]3 years ago

7 0

Because it has more spaces in it it will have less room if the pieces bigger

You might be interested in

Match each set of vertices with the type of triangle they form.

Andrew [12]

Answer: The calculations are done below.

Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

$AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.$

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

$AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.$

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

$AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.$

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

$AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.$

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

$AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.$

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0

3 years ago

Read 2 more answers

Miranda wants to go to her school's Prom night.A ticket costs $110. She has $50 saved, however, to earn the rest she is going to

Alex73 [517]

Answer:

110=50+7(x)

Step-by-step explanation:

6 0

3 years ago

3) Tell whether the matrices are inverses of

Anettt [7]

These matrices ARE inverses of each other!

8 0

2 years ago

Add<br>show all steps please

choli [55]

$\bf \cfrac{3}{x-2}+\cfrac{4}{x-1}-\cfrac{1}{x}$ so, no breaks on the denominator thus, the LCD will be all three then.

$\bf \cfrac{3}{x-2}+\cfrac{4}{x-1}-\cfrac{1}{x}\implies \cfrac{[3x(x-1)]+[4x(x-2)]-[(x-2)(x-1)]}{x(x-2)(x-1)}
\\\\\\
\cfrac{[3x^2-3x]+[4x^2-8x]-[x^2-3x+2]}{x(x-2)(x-1)}
\\\\\\
\cfrac{3x^2-3x+4x^2-8x-x^2+3x-2}{x(x-2)(x-1)}
\\\\\\
\cfrac{6x^2-8x-2}{x(x-2)(x-1)}\implies \cfrac{2(x^2-4x-1)}{x(x-2)(x-1)}$

3 0

3 years ago

Tony has a toolbox in his garage. The toolbox contains 4 hammers, 6 wrenches, 3 pliers, and 4 screwdrivers.

DanielleElmas [232]

Answer:

The answer is A. 6/17

Step-by-step explanation:

the top number is how many wrenches and the bottom number is all of the tools you could possibly get.

7 0

3 years ago