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Fudgin [204]
3 years ago
13

F(x) = 3x^4 is even or odd?

Mathematics
2 answers:
tia_tia [17]3 years ago
8 0

Answer:

even function

Step-by-step explanation:

recall that:

a function is EVEN if and only if f(-x) = f(x) for all x in the domain of f

a function is ODD if and only if f(-x) = -f(x) for all x in the domain of f

we observe that for the function

f(x) = 3x^4

because x has been raised to an even power, that f(x) will always be positive (or zero), regardless of whether x is negative or positive.

i.e

f(x) = f(x)   and   f(-x) = f(x)

This behavior is described by the definition of an EVEN function (given above)

Hence f(x) is an even function

lara31 [8.8K]3 years ago
3 0

Answer:

Step-by-step explanation:

it's even because f(-x)=f(x)

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Answer:

Matrix transformation = \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]

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Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right].

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-5\\-2\end{array}\right]= (5,-2)

Q'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-6\\-3\end{array}\right]= (6,-3)

R'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-2\\-3\end{array}\right]= (2,-3)

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