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11111nata11111 [884]
2 years ago
8

When solving an equation, why is it necessary to perform the same operation on both sides of an equal sign?

Mathematics
2 answers:
Vilka [71]2 years ago
6 0
To get the right answer you must perform the same operation on both sides of the equation because the equation will not be correct if it is not. If you subtract something from one side to make it equal you must subtract it from both sides.
Anna007 [38]2 years ago
5 0
In order to keep the equation right, both sides have to balance each other. When you only perform an operation ( I'm assuming you're talking about division or multiplication) on one side, it messes up the balance because now one side is larger than the other.
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What is the solution to this inequality?
Snezhnost [94]

Answer:

  • \boxed{\sf{D. \quad x < 3}}

Step-by-step explanation:

It is necessary to isolate the term of x from one side of an inequality to find its solution.

<h3>-4x-8>-20</h3>

<u>First, add by 8 from both sides.</u>

\sf{-4x-8+8 > -20+8}

<u>Solve.</u>

-20+8=-12

<u>Rewrite the problem down.</u>

\sf{-4x > -12}

<u>Multiply by -1 from both sides.</u>

(-4x)(-1)<(-12)(-1)

<u>Solve.</u>

<u>Multiply the numbers from left to right.</u>

(-12)(-1)=12

4x<12

<u>Divide by 4 from both sides.</u>

4x/4<12/4

<u>Solve.</u>


<u>Divide the numbers from left to right.</u>

12/4=3

<u>x<3</u>

  • <u>Therefore, the correct answer is D. x<3 (last option).</u>

I hope this helps you! Let me know if my answer is wrong or not.

5 0
2 years ago
Read 2 more answers
Simplify the expression by combining like terms.
andreev551 [17]
4b + 2 is your answer just to help you out if you use cymath you can easily get your answer like i did 

6 0
3 years ago
Solving systems equations: substitution <br> y=6x+5<br> y=4x+5
Andreas93 [3]
6x + 5 = 4x + 5
2x + 5 = 5
2x = 0, x = 0
Y = 6(0) + 5, y = 5
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8 0
2 years ago
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If xsquared+ysquared=57 , xy=3 . find the value of 3(x+y)squared
shepuryov [24]

Answer:

189

Step-by-step explanation:

If you mean this, my answer is 3x63= 189

{x}^{2}  +  {y}^{2}  = 57 \\ xy = 3

{x}^{2}  +  {y}^{2}  + 2xy = 57 + 2 \times 3

{(x + y)}^{2}  = 63

3 {(x + y)}^{2}  = 3 \times 63 = 189

6 0
3 years ago
Select the correct answer.
rusak2 [61]

I don't know i just need points sorry

7 0
3 years ago
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