Question

What the equation parallel to y=-1/5x +7 and containing the point(-10,-3)

Answer 1

The equation of line parallel to$y=-\frac{1}{5} x +7$ and containing the point(-10,-3) is $y=-\frac{1}{5}x-5$

Step-by-step explanation:

We need to write the equation parallel to $y=-\frac{1}{5} x +7$ and containing the point(-10,-3)

The standard form of point slope equation is:

$y=mx+b$

where m is slope and b is y-intercept

Comparing the given equation  $y=-\frac{1}{5} x +7$ with standard form the slope is m= -1/5

Since the lines are parallel the slope of new line is m = -1/5

Now finding b (y-intercept)

Using slope m=-1/5 and point (-10,-3)

$y=mx+b\\-3=-\frac{1}{5}(-10)+b\\-3=2+b\\b=-3-2\\b=-5$

So, b= -5 and slope = -1/5 the equation of new line is:

$y = mx+b\\y=-\frac{1}{5}x-5$

So, The equation of line parallel to$y=-\frac{1}{5} x +7$ and containing the point(-10,-3) is $y=-\frac{1}{5}x-5$

Keywords: Point Slope form

Learn more about point slope form at:

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