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3 years ago

Is a 1/2 bigger than 1/8

Mathematics

1 answer:

Sonja [21]3 years ago

3 0

The answer is yes because 1/2 is equal to 4/8 so 4/8 is bigger than 1/8 :))
i hope this is helpful
have a nice day

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What is 8 3/5 graphed on a number line <br><br> PLZ I NEED HELP ASAP CUZ IM ON A TIMER!

Anton [14]

Answer:

Step-by-step explanation:

8 3/5 on a number line is between 8 and nine

idk how to draw a number line on a computer so ill just tell you how

1. divided the spaces between 8 and 9 into 5 sections ( 3/5 )

2. then mark 3 of those 5 spaces and put a dot or a line at where the 3rd space ends

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3 years ago

A bag has 2 red marbles, 1 blue marble and 4 gold marbles. What is the probability of

Aliun [14]

Answer:

if its wrong then a but pretty sure c xx.

Step-by-step explanation:

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3 years ago

Francisco had a rectangular piece of wrapping paper that was 13 2/3 inches on two sides and 17 inches on the longer sides.

vivado [14]

Francisco's wrapping paper measurements
13 2/3×2=27 1/3
17×2=34

Monica's wrapping paper measurements

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3 0

3 years ago

Circle O has a center at (-2, 10) and a

allsm [11]

Answer:

Step-by-step explanation:

If the point lies on the circle, the distance of the point to the center would be equivalent to the circle's radius since radius is defined as the distance from the center to any point of the circle.

Since length of a radius is half of a diameter,

radius= diameter ÷2

radius= 12 ÷2

radius= 6 units

Let's find the length between each points to see which is equal to 6 units, using the distance formula below.

$distance = \sqrt{(y1 - y2)^{2} + {(x1 - x2)}^{2} }$

A. Distance between 2 points

$= \sqrt{ {(10 + 5)}^{2} + ( - 2 + 6)^{2} } \\ = \sqrt{15 ^{2} + {4}^{2}} \\ = \sqrt{241} \\ = 15.524 \: units$

(to 5 s.f.)

Since the distance is greater than 6 units, point A lies outside the circle.

B. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + ( - 2 + 2)^{2} } \\ = \sqrt{ {6}^{2} } \\ = 6 \: units$

Since the distance of B from the center is 6 units, point B lies on Circle O.

Let's check the other 2 points:

C. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + {( - 2 - 6)}^{2} } \\ = \sqrt{ {6}^{2} + ( - 8)^{2} } \\ = \sqrt{100} \\ = 10 \: units$

Since the distance of point C from the center is greater than 6 units, point C lies outside the circle.

D. Distance between 2 points

$= \sqrt{ {(10 - 8)}^{2} + {( - 2 - 8)}^{2} } \\ = \sqrt{2^{2} + ( - 10)^{2} } \\ = \sqrt{104} \\ = 10.198 \: units$

(to 5 s.f.)

Point D also lies outside Circle O.

8 0

3 years ago

If £25 = 800 rubles, how many £ are in 992 rubles?

WARRIOR [948]

Answer: There are £61.50 in 992 rubles

Step-by-step explanation:

£31 = 500 rubles

£x = 992 rubles

To get c, what we do is simply cross multiply

£x * 500 rubles = £31 * 992 rubles

£x = (£31 * 992 rubles)/500 rubles

£x = £61.504

which is £61.50 to two decimal places

4 0

2 years ago