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nata0808 [166]
3 years ago
13

Round 38,496 to the nearest thousand

Mathematics
2 answers:
anyanavicka [17]3 years ago
7 0
Answer: 38,000

How? For rounding 38,496 to the nearest thousand we need to check its hundreds place.If it is bigger than 5 or is 5 then the number next to it will be increased by 1 and if the number at the hundreds place is below 5 then the number itself and the number behind it will be changed to zero (no change will be added to its next number).

Hope this helps =)
Have a nice day!
iragen [17]3 years ago
3 0
The answer is 38,000
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Use simultaneous equations to solve the following. Three kilograms of jam and two kilograms of butter cost $29 and six kilograms
artcher [175]

Answer:

The cost of 1kg jam is $7 and the cost of 1kg butter is $4

Step-by-step explanation:

Let jam = x

butter = y

3x + 2y = 29 -----(1)

6x + 3y = 54 -----(2)

(1)×2 ->

6x + 4y = 58 -----(3)

(3)-(2) ->

y = 4

suby=4into(2)

6x + 3(4) = 54

6x = 42

x = 7

(Correct me if i am wrong)

6 0
3 years ago
Find the Area of RQP
zhannawk [14.2K]

Answer: 25 units squared

Step-by-step explanation:

Draw a line down from p and go right connecting to r. The units there are equal to the ones on the triangle you were given. 5 horizontally and 10 vertically. 5 times 10 is 50 divided by 2

3 0
3 years ago
(4x^2y^3+2xy^2-2y)-(-7x^2y^3+6xy^2-2y)
Rasek [7]

Answer:

x y^2 (11 x y - 4)

Step-by-step explanation:

Simplify the following:

4 x^2 y^3 + 2 x y^2 - 2 y - (-7 x^2 y^3 + 6 x y^2 - 2 y)

Factor y out of -7 x^2 y^3 + 6 x y^2 - 2 y:

4 x^2 y^3 + 2 x y^2 - 2 y - y (-7 x^2 y^2 + 6 x y - 2)

-y (-2 + 6 x y - 7 x^2 y^2) = 2 y - 6 x y^2 + 7 x^2 y^3:

4 x^2 y^3 + 2 x y^2 - 2 y + 2 y - 6 x y^2 + 7 x^2 y^3

Grouping like terms, 4 x^2 y^3 + 2 x y^2 - 2 y + 2 y - 6 x y^2 + 7 x^2 y^3 = (4 x^2 y^3 + 7 x^2 y^3) + (2 x y^2 - 6 x y^2) + (2 y - 2 y):

(4 x^2 y^3 + 7 x^2 y^3) + (2 x y^2 - 6 x y^2) + (2 y - 2 y)

x^2 y^3 4 + x^2 y^3 7 = 11 x^2 y^3:

11 x^2 y^3 + (2 x y^2 - 6 x y^2) + (2 y - 2 y)

x y^2 2 + x y^2 (-6) = -4 x y^2:

11 x^2 y^3 + -4 x y^2 + (2 y - 2 y)

2 y - 2 y = 0:

11 x^2 y^3 - 4 x y^2

Factor x y^2 out of 11 x^2 y^3 - 4 x y^2:

Answer:  x y^2 (11 x y - 4)

7 0
3 years ago
Rewrite as a cube: 64; −216; 0.008; 1/64; 4 17/27
alukav5142 [94]

64 = 4³

-216 = (-6)³

.008 = 0.2³ . . . . . . 1000 = 10³, 8 = 2³. This is 8/1000, so the cube of 2/10

1/64 = (1/4)³ . . . . . . the inverse of the first number

4 17/27 = 125/27 = (5/3)³

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You can see that it would be helpful to have memorized the cubes of small integers.

4 0
3 years ago
Write a system of equations with the solution (-3,-8) in standard form.
Katyanochek1 [597]

Answer:

y=2x-2

y=3x+1

Step-by-step explanation:

To solve this I will be using the point slope formula

It is as follows

y-y₁=m(x-x₁)

We can choose any m value so I will be choosing m=2

(x₁,y₁) will be (-3,-8) respectively because all we want is for the line to pass through that point

so we have

y-(-8)=2(x-(-3)

We can simplify this to

y+8=2(x+3)

y+8=2x+6

y=2x-2

We then repeat this process but choose a new m (the m value doesn't really matter as long as it's not 0)

I will choose 3

so we have

y-(-8)=3(x-(-3))

Which gives u

y+8=3(x+3)

y+8=3x+9

y=3x+1

3 0
3 years ago
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