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dolphi86 [110]
3 years ago
7

Please help me with this and please select only three answers

Mathematics
2 answers:
ivann1987 [24]3 years ago
8 0
A, E and D are your three answers and
Leona [35]3 years ago
7 0

The answer I'm pretty sure is A,D,E ,but I may be wrong .

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Assume that military aircraft use ejection seats designed for men weighing between 141.8 lb and 218 lb. If​ women's weights are
Mariulka [41]

Answer:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(173.6,49.8)  

Where \mu=173.6 and \sigma=49.8

We are interested on this probability

P(141.8

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

8 0
3 years ago
100 POINTS. ASAP. PLS HELP!
IgorC [24]

Answer:

12.81%

Step-by-step explanation:

2600-5500=20500

20500/16=1281.25

1281.25/100= 12.8125

rounded 12.81%

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2 years ago
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xz_007 [3.2K]
72x

That's is the unknown number multiplied by 72.
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Answer:

12y

Step-by-step explanation: 3(y4)

3×y×4 = 12y

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2 years ago
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