Through:(-1,-5), slope=5

(1 point) Let y=ex/5. Find the differential dy when x=2 and dx=0.2 Find the differential dy when x=2 and dx=0.01

Deffense [45]

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Differential Calculus.

Since, we know this is a definite calculus,

thus we get here as, by using the Chain Rule.

7 0

3 years ago

I can't figure out how to do this question. simplify the imaginary number in the picture above please

Alona [7]

Answer:

-i(6/7)√2

Step-by-step explanation:

$\displaystyle -\sqrt{-\frac{72}{49}}=-\sqrt{-1}\sqrt{\frac{36}{49}}\sqrt{2}\\\\=-i\frac{6}{7}\sqrt{2}$

3 0

3 years ago

tickets at a particular movie theatre have different rates for adults and children. on a friday the theatre sold 4 adult tickets

maria [59]

Using elimination method. Using substitution will cause some fraction problems.

c- child tickets
a- adult tickets

4a + 7c = $83
5a + 6c = $90

multiply by -5

-20a - 35c = -$415
20a + 24c = $360

-11c= -$55
c = $5 child tickets

4a + 7(5)= $83

4a + 35 = $83

4a = $48

a= $12 adult tickets

4 0

3 years ago

If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal

lorasvet [3.4K]

Answer:

a

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

b

The probability is $P(Z > 2.5 ) = 0.0062097$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 800$

The variance is $var(x) = 1600 \ kg$

The range consider is $x_1 = 778 \ kg \ x_2 = 834 \ kg$

The value consider in second question is $x = 900 \ kg$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{var (x)}$

substituting value

$\sigma = \sqrt{1600}$

$\sigma = 40$

The percentage of a cucumber give the crop amount between 778 and 834 kg is mathematically represented as

$P(x_1 < X < x_2 ) = P( \frac{x_1 - \mu }{\sigma} < \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma } )$

Generally $\frac{X - \mu }{ \sigma } = Z (standardized \ value \ of \ X)$

So

$P(x_1 < X < x_2 ) = P( \frac{778 - 800 }{40} < Z< \frac{834 - 800 }{40 } )$

$P(x_1 < X < x_2 ) = P(z_2 < 0.85) - P(z_1 < -0.55)$

From the z-table the value for $P(z_1 < 0.85) = 0.80234$

and $P(z_1 < -0.55) = 0.29116$

So

$P(x_1 < X < x_2 ) = 0.80234 - 0.29116$

$P(x_1 < X < x_2 ) = 0.51118$

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

$P(X > x ) = P(\frac{X - \mu }{\sigma } > \frac{x - \mu }{\sigma } )$

substituting values

$P(X > x ) = P( \frac{X - \mu }{\sigma } >\frac{900 - 800 }{40 } )$

$P(X > x ) = P(Z >2.5 )$

From the z-table the value for $P(Z > 2.5 ) = 0.0062097$

7 0

3 years ago

Which graph represents x - 1 ≤ 3

MAVERICK [17]

The first graph.

The equation is x - 1 $\leq$ 3
In order to solve it, you need to get x by itself.
Add 1 to both sides. 3+1=4
x $\leq$ 4

Since this is your sign $\leq$ the arrow has to point towards the left, and the circle needs to be colored in.

3 0

3 years ago