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Triss [41]
3 years ago
14

I need help understanding rate of change and slope.

Mathematics
2 answers:
Papessa [141]3 years ago
5 0
Rate of Change and Slope are both the same thing. They show the amount of change on the “y-axis” as the “x-axis” moves. I hope it helps... we learned this in class about a month ago.
Evgesh-ka [11]3 years ago
3 0

"Rate of change" is a measure of how much some dependent variable changes with respect to a change in the independent variable. Given a function y(x), the average rate of change over some interval [a,b] is given by what's called the difference quotient,

\dfrac{y(b)-y(a)}{b-a}

If y(x) is a linear function, then the average rate of change is constant regardless of the interval chosen.

A line represents a linear function. The slope of the line represents the linear function's rate of change. We pick any two points on the line, (a,y(a)) and (b,y(b)) where a, and the slope of the line through them is exactly the value of the expression above. Then there are 3 possible scenarios:

(1) If a\neq b, then the slope can be any real number. If y(a)=y(b) happens to be true, then the slope is 0 and the line is horizontal.

(2) If a=b and y(a)\neq y(b), the slope is undefined (some might say infinite) and the line is vertical.

(3) If a=b and y(a)=y(b), then we're talking about just one point. But there are infinitely many possible lines through a single point, so the slope is undefined.

Some examples in practice:

23. The slope of the line through (-5, 0) and (-5, 5) is

\dfrac{5-0}{-5-(-5)}

The x-coordinates match but the y-coordinates don't, so this line is vertical and the slope is undefined (or infinite).

27. The slope is

\dfrac{\frac37-\frac47}{\frac25-\frac15}=\dfrac{-\frac17}{\frac15}=-\dfrac57

Notice the order in which we plug in the given points' coordinates. Always take a to be the lesser of the two points' x-coordinates! The convention is to always take points left to right.

We use the same principles to work backwards:

31. Given a slope of 1/4 through two points (7, 4) and (3, y), we have

\dfrac{4-y}{7-3}=\dfrac{4-y}4=\dfrac14\implies4-y=1\implies y=3

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In this case, we'll have to carry out several steps to find the solution.

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What is the approximate area of a circle with a radius of 10 in?
yKpoI14uk [10]

<em></em>\huge\boxed{\textsf{A.}\ 78.5\ \text{in}^2}

<em></em>

<em>Correction to your question text: diameter, not radius.</em>

The area of a circle is given by:

A=\pi r^2

The radius is half of the diameter.

A=\pi\cdot\left(\dfrac{10}{2}\right)^2

Substitute and solve.

\begin{aligned}A&=\pi\cdot\left(\frac{10}{2}\right)^2\\&=\pi\cdot5^2\\&=\pi\cdot25\\&\approx\boxed{78.5}\end{aligned}

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Step-by-step explanation:

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