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2 years ago

What is 20% of 20 ?

Mathematics

2 answers:

Mariana [72]2 years ago

6 0

The answer is 4.

The easiest way to determine the value of statements like this is to turn the percentage into a decimal and then multiply.

20% * 20

.20 * 20

RideAnS [48]2 years ago

3 0

The answer is 4! :)

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A bakery has 456 dozen cookies how many individual cookies are there

KiRa [710]

I think the answer is 38......,

8 0

2 years ago

Each month Allison gets a $15 allowance and earns $100 working at the theater. She uses the expression 15x+100y to keep track of

Marizza181 [45]

Step-by-step explanation:

The expression for he earning of Allison and her allowance is as follows :

15x+100y

Part A

Variables are x and y. Coefficients are 15 and 100.

Part (B)

There are two terms in this expression. + is used to separate the terms. 15x and 100y are the terms.

Part (C) As $15 shows her earning from allowances. Hence, 15x shows allowance.

3 0

3 years ago

The quadratic regression graphed on the coordinate grid represents the height of a road surface x meters from the center of the

andrew-mc [135]

The height of the surface increases, then decreases, from the center out to the sides of the road.

<h3>What is quadratic equation?</h3>

The polynomial having a degree of 2 is defined as the quadratic equation it means that the variable will have a maximum power of 2.

Let

y------> the height of the surface

x------> the road

we know that

The quadratic regression graphed represent a vertical parabola open downward

The function increase in the interval --------> (-5,0)

The function decrease in the interval --------> (0,5)

therefore

The height of the surface increases, then decreases, from the center out to the sides of the road.

To know more about quadratic equation follow

brainly.com/question/1214333

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1 year ago

Read 2 more answers

The coordinate below represents a town. Curtis’s house is at (-4, -6) and Jean’s house is at (-4, 3).Plot the points where Curti

Fiesta28 [93]

It would take Curtis 45 minutes to ride his bike to Jean's house.

7 0

2 years ago

(x^2y+e^x)dx-x^2dy=0

klio [65]

It looks like the differential equation is

$\left(x^2y + e^x\right) \,\mathrm dx - x^2\,\mathrm dy = 0$

Check for exactness:

$\dfrac{\partial\left(x^2y+e^x\right)}{\partial y} = x^2 \\\\ \dfrac{\partial\left(-x^2\right)}{\partial x} = -2x$

As is, the DE is not exact, so let's try to find an integrating factor µ(x, y) such that

$\mu\left(x^2y + e^x\right) \,\mathrm dx - \mu x^2\,\mathrm dy = 0$

*is* exact. If this modified DE is exact, then

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \dfrac{\partial\left(-\mu x^2\right)}{\partial x}$

We have

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu \\\\ \dfrac{\partial\left(-\mu x^2\right)}{\partial x} = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu \\\\ \implies \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu$

Notice that if we let µ(x, y) = µ(x) be independent of y, then ∂µ/∂y = 0 and we can solve for µ :

$x^2\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} - 2x\mu \\\\ (x^2+2x)\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} \\\\ \dfrac{\mathrm d\mu}{\mu} = -\dfrac{x^2+2x}{x^2}\,\mathrm dx \\\\ \dfrac{\mathrm d\mu}{\mu} = \left(-1-\dfrac2x\right)\,\mathrm dx \\\\ \implies \ln|\mu| = -x - 2\ln|x| \\\\ \implies \mu = e^{-x-2\ln|x|} = \dfrac{e^{-x}}{x^2}$