All categories

3 years ago

What are the real or imaginary solutions of the polynomial x^4-3x^2=-2x

Mathematics

2 answers:

SpyIntel [72]3 years ago

5 0

x⁴-3x²= -2x

Step-by-step:

x⁴-3x²+2x=0

x*(x³-3x+²)=0

x*(x³-4x+x+2)=0

x*(x*(x²-4)+x+2)=0

x*(x*(x-2)*(x+2)+1)=0

x*(x+2)*(x*(x-2)+1)=0

x*(x+2)*(x²-2x+1)=0

Using a²-2ab + b²=(a-b)², factor the expression.

x*(x+2)*(x-1)²=0

Therefore x=0

Therefore x+2=0

(X-1)²=0

X=0

X=-2

X=1

Therefore

x1 is -2

x2 is 0

x3 is 1.

bagirrra123 [75]3 years ago

4 0

Answer:

x = 0 or 1 or -2

Step-by-step explanation:

$x^{4} -3x^{2} +2x=0$

x(x^3-3x+2)=0

x(x-1)^2 * (x+2)0

so x = 0 or 1 or -2

there is no imaginary solutions

You might be interested in

The ratio of 9/5 is equal to

Nutka1998 [239]

The answer is 1 and 4/5. Just divide and put the remainder as the numerator and the numerator stays the same

6 0

3 years ago

Read 2 more answers

Plzzzzzzzzzzz help me

oksano4ka [1.4K]

The second table does not represent a function

6 0

3 years ago

Mrs.Morgan ordered 12 shirts.Three of them were green.What fraction of Mrs.Morgan's shirts were green

ladessa [460]

If there are 12 shirts total and three of them were green, it would be 3 out of 12 or 3/12. Hope this helps! :)

5 0

3 years ago

Find, to the nearest tenth, the area of the region that is inside the square and outside the circle. the diameter of the circle

Doss [256]

Answer:

Option $42.1\ in^{2}$

Step-by-step explanation:

we know that

The area of the region that is inside the square and outside the circle is equal to the area of the square minus the area of the circle

see the attached figure to better understand the problem

Step 1

Find the area of the square

Remember that

The area of the square is

$A=b^{2}$

where

b is the length side of the square

we have

$b=14\ in$

substitute

$A=14^{2}=196\ in^{2}$

Step 2

Find the area of the circle

Remember that

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=14/2=7\ in$

substitute

$A=\pi(7^{2})=153.9\ in^{2}$

Step 3

Find the area of the region

$196\ in^{2}-153.9\ in^{2}=42.1\ in^{2}$

5 0

3 years ago

Read 2 more answers

If a and b are non-negative integers, is ab prime?

andrew-mc [135]

No because ab can be divided by a and b.

8 0

3 years ago

What are the real or imaginary solutions of the polynomial x^4-3x^2=-2x​

What are the real or imaginary solutions of the polynomial x^4-3x^2=-2x