Question

What are the real or imaginary solutions of the polynomial x^4-3x^2=-2x​

Answer 1

x⁴-3x²= -2x

Step-by-step:

x⁴-3x²+2x=0

x*(x³-3x+²)=0

x*(x³-4x+x+2)=0

x*(x*(x²-4)+x+2)=0

x*(x*(x-2)*(x+2)+1)=0

x*(x+2)*(x*(x-2)+1)=0

x*(x+2)*(x²-2x+1)=0

Using a²-2ab + b²=(a-b)², factor the expression.

x*(x+2)*(x-1)²=0

Therefore x=0

Therefore x+2=0

(X-1)²=0

X=0

X=-2

X=1

Therefore

x1 is -2

x2 is 0

x3 is 1.

Answer 2

Answer:

x = 0 or 1 or -2

Step-by-step explanation:

$x^{4} -3x^{2} +2x=0$

x(x^3-3x+2)=0

x(x-1)^2 * (x+2)0

so x = 0 or 1 or -2

there is no imaginary solutions