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3 years ago

15

I’m confused on where to shade these equations? I can do the first 2 but then the last 2 throw me off... I have to shade the are

a that all the points intersect the darkest but they don’t all intersect...

1 answer:

tigry1 [53]3 years ago

4 0

I’m not sure the answer but go into a webpage called Desmos and it will show you

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if 16000 rupees are sufficient for 4 friends to stay in Murree for 6 days. how many days can 6 friends stay in Murree for 28000

gizmo_the_mogwai [7]

Answer:

Answer 7 days...

Step-by-step explanation:

4 FRIENDS,6 DAYS=16000
1FRIEND,6DAYS=4000
1 FRIEND,1 DAYS=4000/6
THERFORE,6 FRIENDS,1DAY=4000/6 *6
6FRIENDS,X DAYS=28000
4000*X=28000(SINCE 6 FRIENDS FOR 1 DAY WAS 4,000)
X=28,000/4000
X=7DAYS

7 0

3 years ago

Rewrite the equation y-3=2(x+4) into slope form

soldi70 [24.7K]

Answer:

Step-by-step explanation:

So we have y-3=2(x+4)

So the first thing we want to do is distribute the 2 in front of the (x+4)

2(x+4) = 2x+8

Which means we have:

y-3=2x+8

Remember we need to get it into the form y=mx+b

As you can see here the 3 is preventing our equation from being in that form to we need to add it to both sides. This leaves us with:

y - 3 + 3 = 2x+8+3

Which gives: y = 2x+11

Therefore the slope form of this equation is y = 2x+11

4 0

3 years ago

-3w-4=w+3<br> solveeeee pleaseeeee

SVETLANKA909090 [29]

Answer: w-3=24

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

F(x, y, z) = z tan−1(y2)i + z3 ln(x2 + 3)j + zk. find the flux of f across s, the part of the paraboloid x2 + y2 + z = 18 that l

Cerrena [4.2K]

$\mathbf F(x,y,z)=z\tan^{-1}(y^2)\,\mathbf i+z^3\ln(x^2+3)\,\mathbf j+z\,\mathbf k$
$\implies\mathrm{div}\mathbf F(x,y,z)=0+0+1=1$

By the divergence theorem, the flux of $\mathbf F$ across the *closed* surface $\mathcal S$ combined with the plane $z=2$ is given by a volume integral over the closed region:

$\displaystyle\iint_{\mathcal S}\mathbf F\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}\nabla\cdot\mathbf F\,\mathrm dV$

So in fact, to find the flux over $\mathcal S$ alone, we'll need to subtract the flux of $\mathbf F$ over the planar portion, oriented outward. First, compute the volume integral by converting to cylindrical coordinates:

$x^2+y^2+z=18$
$z=2\implies x^2+y^2=16\implies r^2=16\implies r=4$

$\displaystyle\iiint_{\mathcal R}\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=4}\int_{z=2}^{z=18-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=128\pi$

If the surface does actually contain $z=2$ , then you can stop here; otherwise, continue.

Now, parameterize the part of the *closed* surface in $z=2$ by

$\mathbf s(r,\theta)=r\cos\theta\,\mathbf i+r\sin\theta\,\mathbf j+2\,\mathbf k$

where $0\le r\le4$ and $0\le\theta\le2\pi$ . We get a surface element

$\mathrm d\mathbf S=(\mathbf s_r\times\mathbf s_\theta)\,\mathrm dr\,\mathrm d\theta=(r\,\mathbf k)\,\mathrm dr\,\mathrm d\theta$

We don't need to worry about the first two components of

and so the surface integral over this region is

$\displaystyle\iint_{z=2\,\land\,x^2+y^2\le16}\mathbf F\cdot\mathrm d\mathbf S=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=4}2r\,\mathrm dr\,\mathrm d\theta=32\pi$

Then the total flux over $\mathcal S$ alone is $(128-32)\pi=96\pi$ .

4 0

3 years ago

26 is 65% of what number?

Elden [556K]

The answer is 40. 25 is 65% of 40

3 0

4 years ago

Read 2 more answers