Answer:
Z> 4
So Z> 2 is true
Step-by-step explanation:
Given that:
Z-2>2
Adding 2 on both sides
Z-2 + 2 >2 + 2
Z > 4
hence the equation Z > 2 is true
i hope it will help you!
A)
y varies inversely as (x-1).
Implies y α 1/(x -1)
y = k/(x-1). Where k is constant of proportionality.
y*(x - 1) = k
when y = 12, x = 1/2
12*(1/2 - 1) = k
12*(0.5 - 1) = k
k = 12*(-0.5) = -6.
k = -6.
Equation connecting x and y
y*(x - 1) = k, recall k = -6
y*(x - 1) = -6
b)
when x = a.
y*(x - 1) = -6
y*(a - 1) = -6
y = -6 / (a -1)
when x = 2a.
y*(2a - 1) = -6
y = -6 / (2a -1)
Difference in y is 1.8
-6 / (2a -1) - -6/(a - 1) = 1.8
-6 / (2a -1) + 6/(a - 1) = 1.8
6 / (a -1) - 6 /(2a -1) = 1.8
6( 1/(a-1) - 1/(2a - 1)) = 1.8
1/(a-1) - 1/(2a - 1) = 1.8/6
1/(a-1) - 1/(2a - 1) = 0.3
((2a - 1) - (a - 1)) / ((a-1)(2a -1)) = 0.3
(2a - 1 -a + 1) /((a-1)(2a -1)) = 0.3
a / (2a² - 3a + 1) = 0.3
a/0.3 = 2a² - 3a + 1
10a/3 = 2a² - 3a + 1
2a² - 3a + 1 = 10a/3
2a² - 3a -10a/3 + 1 = 0
2a² - 19a/3 + 1 = 0
6a² - 19a + 3 = 0
This is a quadratic expression which can be factored.
6a² - 18a - a + 3 = 0
6a(a - 3) - 1(a - 3) = 0
(6a - 1)(a - 3) = 0
6a - 1 = 0 a = 1/6
a - 3 = 0 a = 3.
a = 3 or 1/6
Since a is positive integer, a = 3 only.
Answer:
There are no solutions.
Step-by-step explanation:
3=t+11.5-t
3=11.5 (does not work)
Y=3x+1 should be the answer can I get a crown?
