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nataly862011 [7]
3 years ago
11

Solve for n. 1–3n= – 9+n+2

Mathematics
1 answer:
iris [78.8K]3 years ago
3 0

Answer:

Step-by-step explanation:

1-3n=-9+n+2 ---> -3n-n=-1+-9+2 --> -4n=-8 ---> n=2

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WARRIOR [948]

Answer:

i bleve it is A

Step-by-step explanation:

let me know if im right.

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3 years ago
Help me on question 5A
artcher [175]

Answer:

A

Step-by-step explanation:

because youre doing more bushels its adding and youd be solving for d

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3 years ago
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Solve the following congruence equations for X a) 8x = 1(mod 13) b) 8x = 4(mod 13) c) 99x = 5(mod 13)
xxMikexx [17]

Answer:

a) 5+13k  where k is integer

b) 20+13k where k is integer

c)12+13k where k is integer

Step-by-step explanation:

(a)

8x \equiv 1 (mod 13) \text{ means } 8x-1=13k.

8x-1=13k

Subtract 13k on both sides:

8x-13k-1=0

Add 1 on both sides:

8x-13k=1

I'm going to use Euclidean Algorithm.

13=8(1)+5

8=5(1)+3

5=3(1)+2

3=2(1)+1

Now backwards through the equations:

3-2=1

3-(5-3)=1

3-5+3=1

(8-5)-5+(8-5)=1

2(8)-3(5)=1

2(8)-3(13-8)=1

5(8)-3(13)=1

So compare this to:

8x-13k=1

We see that x is 5 while k is 3.

Anyways 5 is a solution or 5+13k is a solution where k is an integer.

b)

8x \equiv 4 (mod 13)

8x-4=13k

Subtract 13k on both sides:

8x-13k-4=0

Add 4 on both sides:

8x-13k=4

We got this from above:

5(8)-3(13)=1

If we multiply both sides by 4 we get:

8(20)-13(12)=4

So x=20 and 20+13k is also a solution where k is an integer.

c)

[tex]99x \equiv 5 (mod 13)[/tex

99x-5=13k

Subtract 13k on both sides:

99x-13k-5=0

Add 5 on both sides:

99x-13k=5

Using Euclidean Algorithm:

99=13(7)+8

13=8(1)+5

Go back through the equations:

13-8=5

13-(99-13(7))=5

8(13)-99=5

99(-1)+8(13)=5

Compare this to 99x-13k=5 and see that x=-1 or -1+13=12 or 12+13k is a solution where k is an integer.

8 0
3 years ago
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Triangle ABC has vertices located at A( 0, 2), B (2, 5), and C (−1, 7).
LuckyWell [14K]

Answer: See below

Step-by-step explanation:

Triangle ABC has vertices located at A( 0, 2), B (2, 5), and C (−1, 7)

A)

\begin{aligned}&A B=\sqrt{(2-0)^{2}+(5-2)^{2}}=\sqrt{13} \\&B C=\sqrt{(-1-2)^{2}+(7-5)^{2}}=\sqrt{13} \\&C A=\sqrt{(-1-0)^{2}+(7-2)^{2}}=\sqrt{26} \\&A B=\sqrt{13}, B C=A B=\sqrt{13}, C A=\sqrt{26}\end{aligned}

B) Slope of AB line = m₁=3/2

Slope of BC line = m₂=-2/3

Slope of CA line = m₃=-5

C) \mathrm{AB}=\mathrm{BC} \& \mathrm{AB}^{2}+\mathrm{BC}^{2}=\mathrm{CA}^{2}

Therefore, the triangle is a isosceles right angle triangle

6 0
2 years ago
The McConnell's records for January, February, March, and April show that their expenditures totaled $2,004, $1,897, $2,345, and
andrew11 [14]

Answer: $ 2,168

Step-by-step explanation:

As we know,

Average = \dfrac{\text{Sum of terms}}{\text{Number of terms}}

Given: The McConnell's records for January, February, March, and April show that their expenditures totaled $2,004, $1,897, $2,345, and $2,426, respectively.

Average monthly expenditure for the four months

=\dfrac{2004+1897+2345+2426}{4}\\\\=\dfrac{8672}{4}\\\\=2168

Hence, their average monthly expenditure for the four months = $ 2,168.

5 0
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