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Ipatiy [6.2K]
3 years ago
15

A sports car engine delivers 150 kW to the driveshaft with a thermal efficiency of 20%. The fuel has a heating value of 35 000 k

J/kg. Find the rate of fuel consumption and the combined power rejected through the radiator and exhaust.
Physics
1 answer:
Andreyy893 years ago
3 0

Answer:600 kW

Explanation:

Given

Power delivered P=150 kW

Fuel heating value q=35,000 kJ/kg

thermal Efficiency \eta =\frac{Power}{Heat}

0.2=\frac{150}{35,000\times \dot{m}}

where, \dot{m} =mass\ flow\ rate\ of\ fuel

\dot{m}=\frac{150}{35,000\times 0.2}

\dot{m}=0.0214 kg/s

For an Engine

q\dot{m}=P+Q_r , where Q_r=heat\ rejected

Q_r=q\dot{m}-P

Q_r=750-150=600 kW

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